Problems part 3 : Fourier series                                                                        

 

 

 

 

 

 

 

      Prob. 1)    Consider a square wave f(x) of length   2L.   Over the range  [0,2L], this can    

                      be   written as

                     f(x)==2[H(x/L)-H(x/L-1)]-1,  where H(x)is the Heaviside function  .

 

 

FourierSeriesSquareWave

 

 

      Since f(x)==f(2L-x), the function is odd, so a_0==a_n==0, and

 

      b_n==1/Lint_0^(2L)f(x)sin((npix)/L)dx

 

   reduces to

b_n

=

2/Lint_0^Lf(x)sin((npix)/L)dx

 

=

4/(npi)sin^2(1/2npi)

 

=

2/(npi)[1-(-1)^n]

 

=

4/(npi){0 n even; 1 n odd.

 

 

The Fourier series is therefore                f(x)==4/pisum_(n==1,3,5,...)^infty1/nsin((npix)/L).

 

 

 

 

Prob. 2)  Find Fourier series of a saw tooth wave  described by the following equation

 

                     f(x)==x/(2L).

 

 

 

 

 

 

 

 

 

 

 

 

 

         The components of the Fourier series are therefore given by

 

a_0

=

1/Lint_0^(2L)x/(2L)dx

=

1

a_n

=

1/Lint_0^(2L)x/(2L)cos((npix)/L)dx

=

([2npicos(npi)-sin(npi)]sin(npi))/(n^2pi^2)

=

0

b_n

=

1/Lint_0^(2L)x/(2L)sin((npix)/L)dx

=

(-2npicos(2npi)+sin(2npi))/(2n^2pi^2)

=

-1/(npi).

 

The Fourier series is therefore given by

 

f(x)==1/2-1/pisum_(n==1)^infty1/nsin((npix)/L).

 

 

 

 

 

Prob. 3 )    Find Fourier Series of the following function of period  2.

 

 

 

 

Answer

 

 

We have T = 2. Lets find its coefficients :

 

 

 

 

 

 

 

 

a0  we have to calculate of the following , because function does not have definition for   n = 0.

 

 

 

The fourier series is:

 

 

 

 

 

Prob 4)  Find  Fourier series of the following function

 

 

a) Find trigonometric Fourier series of f(t).

b) Graph in the interval  [-4p; 4p].

 

Answer

 

We can extend the period as  2p.  We can obtain the coefficients :

 

 

 

 

 

 

 

 

 

The  a0  coefficient is:

 

 

 

 

Thus the Fourier series is :

 

 

b) Graph of the function:

 

 

 

 

 

 

 

 

 

 

 

 

The point shown values of the function in its discontinuity .

 

 

 

Prob. 5) Find the complex Fourier series of the following f(t) = e-at, where -p < a < p.   With this series we find     .

 

Answer

 

First we fin its coefficients:

 

 

 

 

 

 

Then:

 

 

 

 

 

 

That function is continuous for all values . If we evaluate this in 0 is the same that  f(0), that is , 1. If we evaluate  eint, in  0, we get 1.

 

 

 

Positive terms of in will cancel , thus we can write the function  as :

 

 

 

 

 

 

 

 

Go home

Go to first part : Principles of Signal and Systems Modeling Concepts

Go to second part : System Modeling and Analysis in the time domain

Go to third part : The Fourier series

Go to fourth part : Laplace Transform

 

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