The Minoids Applet. 

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Instructions 
Java Sources 
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Sample Report 
The Polyominoids
The Minoids inside the cubic lattice


Boxes
0 <= x <= 2a
0 <= y <= 2b
0 <= z <= 2c
The numbering convention is such that permits to have an incrementing pattern based in signification, being the x coordinate, the first of all dimensions, the Most Significant Coordinate. In the figure first minoid, the number 1, has coordinates (0, 1, 1), minoid 2 has coordinates (0, 1, 3) and so on. The last minoid, the 29, has coordinates (2, 3, 5).
Minoids bounded by a Box
a + b + c  1 = 5
The maximum order is simply the total number of minoids of the box. For the Box(1,2,3) the maximum order is:ab(c+1) + a(b+1)c + (a+1)bc = 29
This minimum and maximum orders of the Box(1,2,3) indicates this box is the bounding box for some of the 5, 6, 7, ... , 28, 29minoids. Both, the cyan and yellow sections (x=0, x=2) of the Box must have at least 0 minoids and at most b*c = 6 minoids. The green section (x=1) of the Box(1,2,3) must have at least 1 minoid and at most b(c+1) + (b+1)c = 17 minoids.
These are all the translations' boxes for bounding all the dominoids. This java code creates all the translations boxes given the minoid order. 
These are all the rotations' boxes for bounding all the tetrominoids. This java code creates all the rotations boxes given the minoid order. 
Minoids Connections
The four Soft Connections  The eight Hard Connections  The twelve All Connections 
The soft and hard connections are shown in the next figures. The coordinates of the minoids and the coordinates of the line connections are included.
The soft connections are 'weak' bounds between the minoids, since is difficult to get physical minoids mantain rigidity with soft connections. In the other hand, the hard connections are 'strong' bounds between the minoids because is possible to get physical thick minoids with hard connections.Three steps at the right describe how to construct a real minoid.
The two types of connections (soft and hard) give three types of polyominoids:
Translations Polyominoids Counting
Mixed = All  Hard  Soft
The counting is in this way since there are computed bits mask to detect minoids connections, pair by pair. The masks used are of three types: any, hard or soft, and are figured out before the counting takes place.Every 5minoid inside the Box(1,2,3) is represented as a set of 29 bits, 5 ones and 24 zeros. First an incrementing process takes place to move the 5 bits inside the 29 bits space. This reach the total number of testings to the binomial coefficient of 29 over 5, or
29*28*27*26*25 / 1*2*3*4*5 = 118,755
...instead of working wiht the very big number of 2^{29} of ordinary binary counting.The 118,755 resulting 5ones numbers are compared against 6 previouly prepared masks to determine if the suspected pentominoid reaches all the walls of the box for fullfill with the boundings. This java code performs the binomial coefficients incremental machine and checks if the polyominoid bits number satisfy the 6 bounding conditions.
Finally the polyominoids fullfilling the bounding are tested for their total connectivity of the 5 minoids, whether any, hard or soft connection were selected in turn. This java code checks if the already bounded polyominoid bits number satisfy a particular connectivity type.
Minoids' interesting Java Code
public boolean isAnyConnected(Minoid other) { return (isHardConnected(other)  isSoftConnected(other)); } public boolean isHardConnected(Minoid other) { dx = Math.abs(x  other.x); dy = Math.abs(y  other.y); dz = Math.abs(z  other.z); if (dx == 0 && dy == 1 && dz == 1) return true; if (dx == 1 && dy == 0 && dz == 1) return true; if (dx == 1 && dy == 1 && dz == 0) return true; return false; } public boolean isSoftConnected(Minoid other) { dx = Math.abs(x  other.x); dy = Math.abs(y  other.y); dz = Math.abs(z  other.z); if ((x & 1) == 0 && dx == 0) { if ((dy == 2 && dz == 0)  (dy == 0 && dz == 2)) return true; } else if ((y & 1) == 0 && dy == 0) { if ((dx == 2 && dz == 0)  (dx == 0 && dz == 2)) return true; } else if ((z & 1) == 0 && dz == 0) { if ((dx == 2 && dy == 0)  (dx == 0 && dy == 2)) return true; } return false; } 
This java code creates all the translations boxes given a minoids order:
public static Box[] getAllTranslationsBoxes(int order) { int x, y, z, total, count = 0; Box[] boxes = null; for (boolean counting = true; true; counting = false) { for (x=0; x <= order; x++) { for (y=0; y <= order; y++) { for (z=0; z <= order; z++) { total = x*y*(z+1) + x*(y+1)*z + (x+1)*y*z; if (total >= order && (x+y+z) <= (order + 1)) { if (counting) count++; else boxes[count++] = new Box(x, y, z); } } } } if (counting) boxes = new Box[count]; else return boxes; count = 0; } } 
This java code creates all the rotations boxes given a minoids order:
public static Box[] getAllRotationsBoxes(int order) { int x, y, z, total, count = 0; Box[] boxes = null; for (boolean counting = true; true; counting = false) { for (x=0; x <= order; x++) { for (y=x; y <= order; y++) { for (z=y; z <= order; z++) { total = x*y*(z+1) + x*(y+1)*z + (x+1)*y*z; if (total >= order && (x+y+z) <= (order + 1)) { if (counting) count++; else boxes[count++] = new Box(x, y, z); } } } } if (counting) boxes = new Box[count]; else return boxes; count = 0; } } 
This java code checks if the polyominoid bits number satisfy bounding conditions:
private void countTranslations(int order) { if ((order < 1)  (order < minOrder)  (order > maxOrder)) return; translations = 0; if (storeMinoids) vector = new Vector(); Bits number = new Bits(maxOrder, order); recursiveCounting(number, maxOrder, order  1); } private boolean allWallsReached; private void recursiveCounting(Bits number, int bits, int ones) { // If at least one check fails do not count allWallsReached = true; for (int j=0; j < boundingWallsCheckersBits.length; j++) if (boundingWallsCheckersBits[j].isClearAfterAndWith(number)) allWallsReached = false; if (allWallsReached && isConnected(number)) { translations++; if (storeMinoids) vector.addElement(number); } if (ones < 0) return; Bits mask = new Bits(maxOrder, bits); mask.doNot(); // set up a upper mask; mask.doOrWith(new Bits(maxOrder, ones)); // set up a lower mask mask.doAndWith(number); // put the number inside the window Bits window = new Bits(maxOrder, 0); window.setBit(ones); for (int j=1; j < (bits  ones); j++) { window.shiftLeft(false); Bits nextNumber = new Bits(mask); nextNumber.doOrWith(window); recursiveCounting(nextNumber, ones + j, ones  1); } } 
This java code checks if the already bounded polyominoid bits number satisfy connectivity:
private Bits visitedBits = new Bits(); private boolean isConnected(Bits number) { if (number.isClear()) return false; visitedBits.set(maxOrder, 0); Bits rotor = new Bits(maxOrder, 1); int pos = 0; while (rotor.isClearAfterAndWith(number)) { rotor.shiftLeft(false); pos++; } // check the seed as visited visitedBits.doOrWith(rotor); recursiveConnected(pos, number); return (visitedBits.equals(number)); } private void recursiveConnected(int p, final Bits number) { Bits mask = new Bits(connectionsBits[p]); Bits rotor = new Bits(maxOrder, 1); for (int pos=0; pos < maxOrder; pos++, rotor.shiftLeft(false)) { if (rotor.isNotClearAfterAndWith(mask)) { if (rotor.isNotClearAfterAndWith(visitedBits)) { continue; // avoids closed loops } else if (rotor.isNotClearAfterAndWith(number)) { visitedBits.doOrWith(rotor); recursiveConnected(pos, number); } } } } 
Jorge Luis Mireles Jasso
October 20, 2001
Torreón, Coah. México