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  • # 30 - the solution for dilution!

    O.K.! Cheesy pun! But you just might encounter this, since chemical solutions are used all the time for chemistry, and they cost a lot! They�re hard to make, hard to find proper containers to store them in, and difficult to transport to the classroom or laboratory. To save time and space, these solutions are bought, or made in concentrated form called stock solutions. It�s like when you or one of your parents buy concentrated juice from the store, it�s concentrated so they wouldn�t have to buy a whole tub or bottle of juice which will weigh and cost more.

    Some of these chemical solutions have concentrations of 16M, 20M, or even 24M. That�s pretty concentrated! What if a chemist had a stock of a 16 molarity solution of Al(NO3)3 and he wanted to dilute it until he had 1.0 liter of 1.5M. He would have to add water, just like you would add water to concentrated juice, you�re diluting the solution. Now how much water would he add? There is a certain amount of water you need to add to get 1.5M just like you need to add three cans of water to the concentrated juice to get it to taste perfect. Also, how much of the concentrated solution should he dilute? He�s not diluting the entire stock. There is a way to finding this out, but first, there a few things you should know about how teachers and chemists actually dilute their solutions.

    First and foremost of all, a flask is mostly used, most likely a volumetric flask. This is because it allows liquids to be easily held, measured, and easily kept for later(a stopper can be plugged in at the top). When a concentrated liquid is about to be diluted, the right amount is placed in that flask and water is added until the level of the solution reached the mark etched on the neck of the flask.

    So how do you figure out how much of the concentration and water you use? Well you guessed it, there�s a formula, but don�t freak out, it very simple (evil grin).

    Here�s the formula:

    M1V1 = M2V2

    M1 means the molarity of the original, concentrated solution while M2 means the molarity of the new diluted solution, and V1 means the volume (in liters) of the original concentrated solution while V2 means the volume of the new diluted solution.

    For Example: Remember the problem above when a chemist had a stock of a 16 molarity solution of Al(NO3)3 and he wanted to dilute it until he had 1.0 liter of 1.5M? Lets solve that problem.

    Here�s the formula:

    M1V1 = M2V2
    Plug and chug algebra:
    M1= 16 M
    V1=?
    M2 = 1.5 M
    V2= 1.0 liter

    (16M)(x) = (1.5M)(1.0L)

    x = (1.5M)(1.0L)
    (16M)

    x = .094 L or 94 mL

    So the chemist would have to take 94 mL of the concentrated solution, place it in a flask and add water until there�s one liter of solution to get one liter of 1.5 M Al(NO3)3. This Formula just shows that the actual moles of the substance before dilution must equal the number of moles of the substance after solution. In English, that means that when you dilute something, the only thing your adding is water, so you should have the same amount of substance that�s dissolved.
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