TRANSPORT PROPERTIES
      

EFFUSION

We will start with a "pure" random translational motion of gaseous molecules without the influence of any properties. That is the molecules move because they are free to move. If we visualise a container with a small hole for molecules to escape, then those molecules that escape did so because they so happen are traveling in the direction of the hole. There is no influence of any sort to draw them towards the hole.

Such random translational motion out through the hole is known effusion. Let us derive an express for the probability of the molecules escaping through the hole; considering that it is along the x-axis. The first expression we would like to derive will of course be the velocity distribution of the molecules, Φ, along this axis. For this we will again use the Maxwell-Boltzmann distribution function for the velocities along the x-axis.

  Φ = ∫ vxf(vx) dvx     ;   from 0 to ∞
   = ∫ vx [{m/(2πkT)} e-mv(x)�/2kT] dvx   =   (kT/2πm)

[   Mathematics: ∫ xe-ax�dx = 1/(2a)     ;   from 0 to ∞   ]

So if the density of the gas is ρ (= N / V ; N = number of molecules in a volume of V), then the number of molecules moving out of the hole per unit time will be given by, ф.

ф = Φ ρ = (kT/2πm)ρ


Thomas Graham

For a hole with area Ao;

Rate of effusion = (kT/2πm)ρAo = pAo / (2πMRT)

[   Substituting N/V = p / kT from the perfect gas equation.   ]

Graham's Law of effusion (1846): The rate of effusion is inversely proportional to its molar mass.

Tutorial 3

The rate of effusion of hydrogen gas is 6 times that of an unknown gas. The density of hydrogen gas is 0.090 g dm‾�, identify the unknown gas.      Answer

Sometimes it is more relevant to express ф in terms of the mean speed of the molecules, ĉ. Applying the Maxwell-Boltzmann distribution function to the speed of the molecules.

  ĉ = ∫ sf(s) ds     ;   from 0 to ∞
   = ∫ s [4π {m/(2πkT)}3/2 s� e-ms�/2kT] ds

[   Mathematics: ∫ x�e-ax�dx = 1/(2a�)     ;   from 0 to ∞   ]

Soĉ = (8kT/πm)
Andф =� ĉρ

FLUX

There are three other types of translational motion brought about by "the uneven distribution of properties". They are diffusion, thermal conductivity and viscosity. The rate of movement of such properties is known as flux, ξ, and is directly proportional to the property gradient.

Such translational motion is governed by two factors. The random translational motion, ф, and the collision between molecules. That is a fraction of the molecules move forward while some are slowed down because they have collided with other molecules.

Let us derive an expression for the frequency of collision. From tutorial 2 we have derived the collision frequency, the number of collisions made by a molecule per unit time, to be   πd�cp / kT. So the mean free path, λ, the distance the molecule travelled before hitting a molecule is;

λ c / (πd�cp / kT) kT / πd�p.

The proportionality constant was determined to be 2‾. So λ = kT / (2πd�p).

The equation for flux can then be expressed as;

ξ ф x λ x {property factor} x {property gradient}

Let us illustrate this with the diffusion of gases

DIFFUSION

Diffusion is the translational motion brought about by a difference in concentration. For example when we release a smoke at one end of a tube it will eventually spread until it is distributed evenly throughout the tube.

Consider the gas moving for a distance of 2λ. The change in density, dN / dV = (dN / dx) x (dx / dV), where dV = unity. So;

dф / dx = � ĉρ = �ĉ {-2λ (dN / dx)}

Of course this is not an exact expression as many assumptions were made in its derivation. It was found that a better fit would be;      ξ = - (⅓ĉλ) (dN / dx)}

THERMAL CONDUCTIVITY

Thermal conductivity is the translational motion brought about by a difference in energy of the molecules. If you heat a gas at one end of the tube eventually the gas at the other end of the tube will get hot.

ξ = � ĉ d(ρ energy per molecule) / dx = � ĉρ d(energy molecules) / dx

Now pV = force distance = energy = kT. However there is also a partition of energy for the different motions - translational, rotational, and vibrational - in the molecule. So the relevant term to use here will be the heat capacity of the molecule at constant volume per molecule, Cv,m.

ξ = � ĉρ {-2λ Cv,m (dT / dx)}

A better fit would be;      ξ = - (⅓ĉλCv,mρ) (dT / dx)}

In general   Cv,m = � {3 + ξ(rotational) + ξ(vibrational)} k. So more monoatomic gases (noble gases) there will be no vibrational or rotational motion so Cv,m = 3k / 2.

For linear molecules at normal temperature ξ(rotational)=2 for linear molecules and ξ(rotational) = 3 for non-linear molecules. ξ(vibrational) is only important at high temperatures.

VISCOSITY

Viscosity is the translational motion brought about by a difference in momentum of the molecules.

ξ = � ĉ d(ρ momentum per molecule) / dx = � ĉρ d(momentum) / dx

ξ = � ĉρ {-2λ m (dvx / dx)}

A better fit would be;      ξ = - (⅓ĉλmρ) (dvx / dx)}

SUMMARY

PROPERTYGRADIENT COEFFICIENT
UNITS
Diffusion- dN / dxof diffusion, D = (⅓ĉλ) m� s‾�
Energy- dT / dx of thermal conductivity, k = (⅓ĉλ) (Cv,mρ)JK‾� m‾� s‾�
Momentum- dvx / dxof viscosity, ŋ = (⅓ĉλ) kg m‾� s‾�

Tutorial 4

What do you understand by the term coefficient?      Answer

The classical method for determining the viscosity coefficient of a gas is to measure the volume flow of the gas through a cylindrical tube of radius r and length L, under a pressure of p1 with the outlet at a pressure of p2. According to Poiseulle's equation;

dV / dt = (p1� - p2�)πr4 / 16Lŋpo

where po is the pressure at which the volume was measured, usually the same as p2.

Tutorial 5

Prove that the flux for thermal conductivity and viscosity is not dependent on the pressure of the system.      Answer

Tutorial 6

Compute for the coefficient of thermal conductivity of nitrogen gas (r =0.110 nm) at SATP. Repeat the calculation for chlorine (r = 199 nm). What factors of a molecule determined the magnitude of k?     
Answer

Tutorial 7

Air was forced through a cylindrical tube 100 cm long and 1.00 mm in diameter at 764 torr of pressure. The gas escaped at 760 torr at the rate of 72 cm� in 100 s at SATP. What is the viscosity of air at SATP?      Answer

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