END OF CHAPTER PROBLEMS
A solution contains 15 grams of NH4Cl in water and is 8.5% NH4Cl. What is the mass of water present?
% = ( part / whole ) x 100
8.5% = ( 15 grams NH4Cl / solution ) x 100
% = ( solute / solution ) x 100
0.085 = 15 grams NH4Cl / solution
�solution� = 176.47 grams
176.47 gram solution - 15 gram NH4Cl = 161.47 grams