END OF CHAPTER PROBLEMS
What mass of CaCl2 is in 2.58 L of a 0.0784 M solution?
M = # of moles of solute / # of Liters of solution
# of moles of solute = 0.2
0.0784 moles/Liter = # of moles of solute / 2.58 Liters of solution
0.2 moles CaCl2 x 111 grams/1 mole = 22.2 grams of CaCl2