Lets just say that the Enterprise has 10 transporter pads which can transport 10 people each.
To operate all of those pads simultaneously would require AT LEAST:

4.8 x 10^31 bytes

Let's put this in today's terms:
4.8 x 10^31 bytes is:

• TEN TRILLION TRILLION CD ROMS (uncompressed)
• About 100 QUINTILLION times more RAM than is availale in all computers on the Earth today.
• A string of 4MB simms 113 MILLION LIGHT YEARS long.

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