Visual Basic.NET by Nitin Chopra

System Tray Icon
and Context Menus

Ok now we need to specify the icon that is to be displayed. Also we will associate the context menu, set the tooltip text on the icon. Finally we will set the visible property of the NotifyIcon to True (This step is very important otherwise icon won’t be displayed) 

      ' The Icon property sets the icon that will appear
      ' in the systray for this application.
      nIcon.Icon = New Icon("myicon.ico")

      ' The ContextMenu property sets the menu that will
      ' appear when the systray icon is right clicked.
      nIcon.ContextMenu = Me.ContextMenu

      ' The Text property sets the text that will be displayed,
      ' in a tooltip, when the mouse hovers over the systray       ' icon.
      nIcon.Text = "My NotifyIcon Example"
      nIcon.Visible = True

Now you can handle the events corresponding to either the icon or the menu icon. For example:-

Private Sub nIcon_DoubleClick(ByVal sender As Object, ByVal e As System.EventArgs) Handles nIcon.DoubleClick

      ' Show the form when the user double clicks on the icon.
      ' Set the WindowState to normal if the form is minimized.
      If (Me.WindowState = FormWindowState.Minimized) Then
            Me.WindowState = FormWindowState.Normal
      End If

      ' Activate the form.
      Me.Activate()

End Sub

Private Sub menuItem1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles menuItem1.Click

        'exit the application
        MsgBox("Exiting Application")
        End

End Sub

On the click event show the context menu at a position defined by you.

Private Sub nIcon_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles nIcon.Click

        ctxtMenu.Show(Me, New System.Drawing.Point(300, 300))

End Sub

ContextMenu.Show() function is used to display the menu at a specified position on the screen.

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