| ALGEBRA REVIEW |
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SOLUTIONS TO ALGEBRA REVIEW 1.
x2 – 1 = 0 2.
Expand (x-4)3 (x-1)(x+1) = 0 = (x-4)(x-4)(x-4) x
= 1; x = -1
= (x2 – 8x + 16)(x – 4) = x3 –
8x2 + 16x – 4x2 +32x –64 = x3 –12x2 +
48x –64 3.
√ 1.44 = 1.2 4. Factor
x3 + 1
5. Simplify x2
+4x +3
= (x+3)(x+1) x+1
= x + 3 |
| JOE TUNCAVAGE B.S. CHEMISTRY PROFESSIONAL TUTOR, MATH/SCIENCE |
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1. x2 – 1 = 0 2. Expand (x-4)3 = 3. (1.44)0.5 = 4. Factor x3 + 1 = 5. Simplify the expression: x2 + 4x + 3 x + 1 |
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