Prakata 

Tugasan  Bernas

Masalah Non Rutin

Rekreasi Matematik 

Biodata Ahli

Tugasan Ilmiah

Sinopsis Kursus

Pautan

Can you find five consecutive whole number that are all positive and such that the sum of the squares of the two largest numbers is equal to the sum of the squares of the three smallest?

 Let n be then number in the middle of the series. We have the relationship

(n + 1)² + (n + 2)² = n² + (n - 1)² + (n - 2)²

Expanding and simplifying gives us

n(n-12) = 0

The only acceptable solution is n = 12. The five consecutive whole numbers are

10, 11, 12, 13 and 14