The circuit to the right has a 10.0
volt battery connected to a 0.0200 farad capacitor. What is
the charge on the top plate of the capacitor?
A. - 0.200
C
C. - 0.00200 C
B. + 0.200
C
D. + 0.00200 C
Q = CV = 0.0200 F x 10.0 v = 0.200 C
The top plate of the capacitor is connected to
the negative end of the battery. There will be an excess of
electrons of the top plate and it will have a negative charge.
