Question: I want to figure out the maximum wire distance that can be used for a row of evenly spaced speakers on 22 AWG wire. How do I do this ?

Answer: It's possible to figure this out with Option C (press "y" when prompted for this type of calculation) - see figure below. Please note that this program assumes that the power supply is located at the determined spacing distance from the first speaker or horn. For example, if the program determines that you can space speakers 25 feet apart on 24 AWG wire, it is assumed that the power supply will be no more than 25 feet from the first speaker.
Added 2/5/2000

Question
:  I was just using Option A and noticed something. When I enter a 90 dB room with dimensions of 515' long by 315' wide with a 22 foot mounting height, the program suggests 77 fifteen watt horns. When I increase the mounting height to 36 feet, the program suggests 60 fifteen watt  horns. Why ?

Answer
:  First of all, remember that Option A initially returns a suggested configuration. Usually this suggestion is just one of many possible combination of horn type and spacing that may be used. There are numerous factors that are used to arrive at the one configuration that is initially suggested. The #1 criteria is whether or not any horn will work. Criteria #2 is to use the default spacing limits built into the program (shown here) .    

In your example, the program is initially attempting to design for a 45' spacing. This is the default spacing for fifteen watt horns at 90 dBspl.
The program first determines if a fifteen watt horn can produce enough audio at 45 foot spacing with respect to the mounting height you've entered.

Once this has been determined, the program divides each room dimension by 45 feet to come up with a number of rows as well as a number of horns per row.
In this case that's 7 horns per row and 12 rows or a total of 84 horns.
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