♥ example 2: a pillar is 6 feet and 11 inches. what is its height if measured in meters?
   given = 6'11" --> m

I. first convert feet into inches [12 inches = 1 foot]
6.0ft x 12in/1ft <-- cancel ft from the denominator of 12 in/1 ft since it has the same unit as 6.0ft
6.0 x 12in = 72in

II. combine 48 feet with 11 feet to complete the sum
72in + 11in = 83in

III. convert inches to centimeters [2.54 cm = i inch]
83in x 2.54cm/1in <-- cancel in for the same reason given above
83 x 2.54cm = 203.2 <-- round off 203.2
203 cm




♥ example 3: a room is approximately equal to 7.20m in length, 5.00m in width, and 2.50m in height.
                    what is it's area if the floor is in ft² and the volume in ft³?
given: A = LxW [ft²]         V = LxWxH [ft³]

I. get the length [1m = 3.28ft]
7.20m x 3.28ft/1m <-- cancel m
7.20 x 3.28ft
23.616ft

II. get the weight [1m = 3.28ft]
5.00m x 3.28ft/1m <-- cancel m
5.00 x 3.28ft
16.4ft

III. get the height [1m = 3.28ft]
2.50m x 3.28ft/1m <-- cancel m
2.50 x 3.28ft
8.2ft

IV. get the area
23.616 x 16.4 = 387.3ft²

V. get the volume
23.616 x 16.4 x 8.2 = 3178.32ft³




♥ example 4: a piece of wood has a mass of 12.50g and a volume of 1.05cm³. determine its density in kg/m³
   given = wood mass: 12.50g ; volume: 1.05cm FIND wood in kg/m³

I. get measurement of mass ['kilo-' = 1x10³]
12.50g x 1kg/1x10³g <-- cancel g
12.50 x 1kg/1x10³
.0125kg

II. get measurement of volume ['centi-' = 1x10^-2]
1.05cm³ x (1x10^-2m)³/(1cm)³
*cube 1x10^-2m)³ to be able to cancel cm³ from 1.o5cm³*
1.05 x (1x10^-2m)³
1.05x10^-6

III. get the density [density = mass/volume]
.0125g/1.06x10^-6m³
1.19x10⁴









**credits: sir lasap's notes (As copied from Asha Singh of JG)