Stay away from the cords!  Today we’ll try the lesson on the white 
Screen.  Listen to music and stop talking as you do you warmup!

Warmup
	Find the vertex and the zeroes of
		
completing the square
		
	zeroes = roots = x-intercepts
	FACTOR and set y = 0 m: -6, a: + 5, 6, -1
		Roots x +3 = 0 and 2x – 1 = 0
					x = -3 and		x = ½ 

After I want to talk about p. 275 #5ab, are there any other questions
5a) Graph f(x) = -2(x + 1)2 + 3
	All we need is the vertex and which way it opens
	Vertex (-1, 3) opens down (because of the -2)
b) Graph f-1(x)
	Flip the points in the vertex 
	Vertex of f-1(x) is (3, -1)
	Find the equation of f-1(x)
		Set y = f(x), switch x and y, solve for y
			please put it in (or leave it in)
					vertex form!!!
			
Properties of Inverses (Continued)

	When we take the inverse of a parabola, it is not a function.
(think of a sideways parabola).  By restricting the domain of f(x),
we can make f-1(x) a function.  We only need half of the parabola,
so we will restrict at the vertex.

Example 2: For f(x) = -3x² + 12x – 8,
	a) determine the vertex of the parabola
			Vertex (2, 4) opens down
	b) Find f-1(x)
		Set y = f(x)
			
	c) Restrict the domain of f(x) so f-1(x) is a function
		What’s the entire domain and range?
		Remember our vertex was (2, 4) and opens down
		d: {x | x € R}	(any value)
		r: {y | y ≤ 4, y € R} (vertex was (2, 4) and values lower)

	To make the inverse a function, just choose one branch of
the parabola.  This can be x ≥ 2 or x ≤ 2.  Let’s choose x ≤ 2.

	d) State the domain and range of f-1(x).
		Remember that the domain and range switch, so..
		d: {x | x ≤ 4, x € R}
		r: {y | y ≤ 2, y € R}  (because we restricted the 
					domain of f(x) above)

********** Restrict the domain of f(x) so that f-1(x) is a function.

HW p. 274 #3, 10, p. 295 #16, 17
	Also, shovel your driveway for your parents this 
	weekend.

2b)