10 SCREEN 12 20 WINDOW (-1, 5)-(38, -25) 30 LINE (0, 0)-(4, 4) 40 LINE (4, 4)-(4, 0) 90 LINE (-1, 0)-(5, 0) 100 LINE (0, 5)-(0, -1) 110 PAINT (3, 2) 115 LOCATE 1, 20 120 PRINT "Center of Mass by Triple Integral" 130 CIRCLE (3, 9 / 5), .2, 1 140 LOCATE 7, 1 150 PRINT "Problem: Find the center of mass under z^2=xy above y=x,y=0,x=4 in plane z=0" 160 PRINT " "; CHR$(244); "4"; CHR$(244); "x"; CHR$(244); "(xy)^1/2 "; CHR$(244); "4"; CHR$(244); "x "; CHR$(244); "4 "; CHR$(179); "y=x" 170 PRINT "Mass M="; CHR$(245); "0"; CHR$(245); "0"; CHR$(245); "0 dzdydx="; CHR$(245); "0"; CHR$(245); "0 (x^1/2)(y^1/2)dydx="; CHR$(245); "0 (x^1/2)(2(y^3/2)/3"; CHR$(179); "y=0 dx" 180 PRINT " "; CHR$(244); "4 "; CHR$(244); "4 "; CHR$(179); "4" 190 PRINT "="; CHR$(245); "0 (x^1/2)(2/3)x^(3/2)-0dx="; CHR$(245); "0 (2/3)x^2dx=(2/3)(x^3)/3"; CHR$(179); "0 =128/9" 200 PRINT " "; CHR$(244); "4"; CHR$(244); "x"; CHR$(244); "(xy)^1/2 "; CHR$(244); "4"; CHR$(244); "x "; CHR$(244); "4 "; CHR$(244); "x" 210 PRINT "Moment of yz Myz="; CHR$(245); "0"; CHR$(245); "0"; CHR$(245); "0 xdzdydx="; CHR$(245); "0"; CHR$(245); "0 x(xy)^(1/2)dydx="; CHR$(245); "0 x^(3/2)"; CHR$(245); "0 y^(1/2)dydx" 220 PRINT " "; CHR$(244); "4 "; CHR$(244); "4 "; CHR$(179); "4" 230 PRINT "="; CHR$(245); "0 x^(3/2)(2/3)x^(3/2)dx=(2/3)"; CHR$(245); "0 x^3dx=(2/3)(x^4)/4"; CHR$(179); "0 =2(4^3)/3=128/3 =Myz/M" 240 PRINT " "; CHR$(244); "4"; CHR$(244); "x"; CHR$(244); "(xy)^1/2 "; CHR$(244); "4"; CHR$(244); "x "; CHR$(244); "4" 250 PRINT "=3 Mxz="; CHR$(245); "0"; CHR$(245); "0"; CHR$(245); "0 ydzdydx="; CHR$(245); "0"; CHR$(245); "0 y^(3/2)x^(1/2)dydx="; CHR$(245); "0 (2/5)x^(5/2)x^(1/2)dx" 260 PRINT " "; CHR$(244); "4" 270 PRINT "=(2/5)"; CHR$(245); "0 x^3dx=(2/5)(4^4)/4=128/5 =Mxz/M=9/5" 280 PRINT " "; CHR$(244); "4"; CHR$(244); "x"; CHR$(244); "(xy)^1/2 "; CHR$(244); "4"; CHR$(244); "x "; CHR$(244); "4 "; CHR$(244); "x "; CHR$(244); "4" 290 PRINT "Mxy="; CHR$(245); "0"; CHR$(245); "0"; CHR$(245); "0 zdzdydx="; CHR$(245); "0"; CHR$(245); "0 (1/2)xydydx=(1/2)"; CHR$(245); "0 x"; CHR$(245); "0 ydydx=(1/2)"; CHR$(245); "0 x(x^2)/2dx" 300 PRINT " "; CHR$(244); "4" 310 PRINT "=(1/4)"; CHR$(245); "0 x^3dx=(1/4)(4^4)/4=16 =Mxy/M=9/8" 320 PRINT "So the center of mass is at (3,9/5,9/8)" 330 SYSTEM