Hardy-weinberg

 

1) q²= 360/1000 = .36

            q=.6  so p = .4

            homo dominant = p² = (.4)² = .16 x 1000 = 160

            homo recessive = 360 given

            hetero = 1000- 360 – 160 = 480

 

2) 25% are recessive

            so q² = .25, q= .5, so p = .5

            homo dominant = p² = (.5)² = .25 x 500 = 125

            hemo recessive = .25 x 500 = 125 given

            hetero = 500-125-125 = 250

 

3) 510 show dominance so 1000 – 510 = 490 are homo recessive

            490/1000 = .49 = q², so q = .7 so p = .3

            homo dominant = p² = (.3)² = .09 x 1000 = 90

            hetero = 1000 – 490 – 90 = 420

 

4) 16% homo recessive

            .16 = q², so q = .4, p = .6

homo recessive = q² x 2000 = 320

homo dominant = p² = (.6)² x 2000 = 720

            hetero = 2000 – 720 – 320 = 960

 

5) 4% = q², so q = .2 and p = .8

            homo recessive = 4% x 1000 = 40

            homo dom = p² = (.8)² x 1000 = 640

            hetero = 1000-640- 40= 320

 

6) 91% = dominant so 9% = recessive

            q²= .09 so q = .3, p = .7

            dom allele is 70 %