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This game is played on the turntable.� This pricing game offers four two-digit prizes and a car (usually in the $20,000-$25,000 range).� All of their prices are listed with the tens digit from each missing.� There are five red number blocks for this game.� Each block is the missing digit for one of the prizes.� The contestant has 30 seconds to put the right numbers in the right price to win the prize.� The contestant wins each prize s/he has right.� After the contestant makes his/her choices, s/he finds out how many of the prices s/he has right.� If the contestant has less than 5 numbers right, s/he can choose to have another 30 seconds to "switch" the numbers s/he feels are wrong with the numbers that are hopefully correct (hence the name "Switcheroo").� After this time, the contestant gets no more chances to make changes.� The contestant is once again shown how many prizes s/he has won, and then s/he is shown what prizes s/he has won (hopefully the car if nothing else).� The contestant wins each prize with the correct price. |
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This pricing game isn't nearly as hard as the contestants make this game seem.� There's really just one basic rule in this game--place the number in the price of the car LAST!!! NOT FIRST, LAST!� No one ever has any idea what the tens digit in the price of a car is, yet this is usually the prize contestants attack first.� That's not how to win this game.� While Rod Roddy is describing the two-digit prizes, think about what their prices might be.� Then when you see the numbers you have to use, pick the number that will make the price closest to what you thought the price was.� The one remaining number must belong in the price of the car.� Note:� if you don't have all 5 prizes right, one of the prizes you probably don't have right is the car; even if you have already won 3 prizes, don't be afraid to make the switch (however, of course, this does not apply to those contestants who just randomly put the numbers anywhere; sadly, over half of Switcheroo contestants seem to be this way). |
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