money

This game is played on the turntable. The prize is a car! There are nine 2-digit combinations of numbers on the board. Seven of them have a "$" behind them; the other two have half of a car behind them, either the front half or the back half. The middle digit is given to you. You must pick out the first two numbers in the price of the car and the last two numbers. If you pick out both sets of numbers before you pick four incorrect choices, you win the car AND money in the value of any incorrect choices you have made. If you pick four incorrect choices before you find both sets of numbers in the price of the car, you win only the total of the four incorrect choices.

Avoid ANY numbers higher than 65! They're wrong. They are NOT the last two numbers in the price of the car, so don't bother picking either! If 20 or 25 is ever a choice for the last two numbers in the price of the car, pick that. It is almost always correct. Usually, there are three possibilites for the first two numbers in the price of the car. If, however, you notice there are four choices for the first two numbers instead of three, one of the choices is correct for the last two numbers. Also, you may want to look for the last two numbers before you look for the first two numbers, just so if you lose, you will get a little more money. Also, if you find the last two numbers on your first guess, pick the highest number on the board. You won't lose, assuming you know the first two numbers is one of three possibilities, but you'll win the car AND a little extra money.