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This game is played behind the curtain. There are 3 prizes in this game--a 2-digit prize, a 3-digit prize, and a car. The contestant gets ten chances to win all 3 prizes. First, the contestant tries to win the 2-digit prize. The contestant is given 3 numbers, and s/he must use 2 of those 3 numbers to write down the price of the prize. If the contestant is right, s/he gets to try to win the next prize (unless it was chance #10). If wrong, and there is at least one chance left, the contestant tries again to write down the price of the prize (but since there are only 6 possible combinations, a contestant would have to be pretty stupid to still be trying to win this prize on chance #10). If wrong, and there are no chances left, the contestant wins whatever prizes s/he has already won only. For the 2nd prize, there are 4 numbers given, and the contestant must use 3 of the 4 numbers for its price. For the 3rd prize, the car, there are 5 numbers given, and the contestant must use all 5 numbers for its price. The contestant wins all 3 prizes if s/he can get all of the prizes' prices in ten chances or less. Also, this game has a "Ten Second" rule--if the contestant doesn't write down the price in 10 seconds, s/he loses that chance (though I have never seen them ever enforce this rule, and I have seen contestants take about half a minute before). |
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This must be the easiest car game on TPiR. There is one really BIG secret for this game that makes it, well, 10 times easier--MAKE SURE THE ZERO IS THE LAST DIGIT!! Having said this, the first prize occasionally does not have a 0, but it will have a 5--that 5 is the last digit. But for the 2nd and 3rd prizes, the zero is ALWAYS used last. I have yet to see an exception to this--this is the ONLY car game that ALWAYS has the same digit last, the zero. It is NEVER 5 or 9. Now, keeping the zero last, there're only 2 possible combinations for the first prize. If you know how to play, you will at worst have used 2 chances on this prize. For the 3-digit prize, you should be able to eliminate one of the digits as being the first number. For example, if the prize is a dishwasher, and the three non-zero numbers are 3, 5, and 8, can you guess which one surely is NOT the first digit? (It's the 8.) So this prize might gobble up 4 chances, so at worst you will only have 4 chances for the car, but that IS enough to win. Again, I can't stress enough that the last digit for the car is ALWAYS zero. The first two digits for the car aren't hard to figure out (if necessary, ask again what kind of car it is). You can limit the first two digits to one of two combinations (usually a 1 with 2 possible second digits, but ocassionally a 1 with a high 2nd digit or a 2 with a low second digit). There is no definite pattern for which of the remaining non-zero numbers is 3rd or 4th (but the fourth digit is usually an odd number). Again the ZERO is LAST. This leaves only 4 possible combinations for the price of the car. So at worst, if it took 2 chances to win the first prize, 4 chances to win the second prize, and 4 chances to win the 3rd prize, that totals TEN CHANCES. So there is no excuse for losing this game. It's really frustrating to see that many people have not even been winning the second prize lately (I want to "punch a bunch" these contestants ;) I will admit, however, this game was a little harder with 4-digit cars. There were 6 possible combinations the car could be, for a total of 12 chances. But that was then, and today is now (how many pricing game references am I going to make here?). Today there is NO excuse for not winning the car! |
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