Harmonic Oscillator Eigenfunctions
Simplifying the Differential Equation
for the Harmonic Oscillator
The
annihilation and creation operators are defined, respectively, as
where Let where
i.e. K = mw02, m is the mass of the particle and K is the
spring constant. In terms of = x and Eq. (1) becomes
To simplify
Eq. (2) let
In terms x Eq.
(2) becomes
The
time-independent Schrodinger equation for the harmonic oscillator, in terms of the
creation and annihilation operators is given by
To evaluate
the quantity in brackets first express in
terms defined in Eq. (4), i.e.
Substituting
Eq. (6) into Eq. (5) gives the simplified differential equation for
Finding
the Eigenfunction corresponding to the Ground State
Returning to
the annihilation operator the equation , in terms of Eq. (4), becomes
We can
choose the sign of to be
positive since this amounts to multiplication by an arbitrary phase factor. Therefore
A0 is chosen such that , i.e.
Note:
Therefore becomes
can also be expressed in terms of x
as follows.
As above
with A0 the constant B0 is chosen such that when is expressed in terms of the variable x.
Therefore
Recall that x = bx � that dx = bdx � dx
= dx/b. Eq. (13)
then becomes
Solving for B0 gives
Finding
cn
Notation: Let be used in what
follows.
As shown
elsewhere is
proportional to . I.e.
Our next
task is to determine c1 which is determined as usual by demanding . Note
that . Thus
The arbitrary
phase factor will always be chosen to have the value of unity. Similarly is proportional to . I.e.
Therefore
In general
We therefore have
Eq. (22) then
becomes
Once again we
follow the same procedure above for Eq. (21) but now for n = 3 to get
This process
can be continued. The general results are therefore given by
In terms of
the eigenfunctions we have
where
When the operator acts on exp(-x2/2)
results in an nth order polynomial multiplied by exp(-x2/2),
i.e.
Hn(x) are the Hermite polynomials.
The first 5
eigenfunctions are listed below
A
Few Useful Relations
Two useful
relations are
Eq. (31a) is
readily derived as follows. We have from Eq. (27)
Eq. (31b)
obtained by multiplying Eq. (25) by to
give