Chapter 8 Question 3
 
a. What do you understand by the ‘average separation between molecules’? Explain how the average separation is related to the measurable volume of a given substance.  3 marks
 
The average separation between molecules is the distance between the centers of adjacent molecules when they are regarded as evenly distributed in a given volume. 1
c0803a.gif (9516 bytes) 1
Since the size of a molecule is very small (especially in a gas), we can regard each molecule as occupying a cube of side D. N such cubes make up the total volume V. Thus, the average separation between molecules is
  1
 
b. When liquid turns into gas under atmospheric pressure, the typical increase in volume is 750 times as great. Find a value for the typical increase in the average separation. 2 marks
 
The ratio of volumes in gaseous form to liquid form is
 
Thus, the ratio of separations is
  2
 
c. Sketch a graph to show the variation of the intermolecular force with the separation between the centers of two molecules.
    A sample of gas is contained in a fixed volume vessel. Mark on your diagram to show
i)    the relative positions of the molecules during collision.
6 marks
ii)     the normal separation at low temperature.  
iii)     the normal separation at high temperature.  
 
c0803b.gif (9748 bytes)
Note:
  1. When the molecules collide, the molecules penetrate into each other. Work is done against the intermolecular repulsion. (k.e. is converted into intermolecular p.e. temporarily). Thus, their separation is less than the equilibrium separation ro.
  2. In a gas, the normal (average) separation depends on the volume of the gas and the amount of molecules only. It is independent of the temperature.
d. The van der Waal’s equation of state is written as

    ( p + a ) (V - b) = n R T

where a and b are quantities depending on n.
Explain how this equation describes the behaviour of a real gas.

5 marks
 
Unlike an ideal gas, there is intermolecular force in a real gas.
Intermolecular attraction force
c0803c.gif (7782 bytes) 0.5
This reduces the pressure of the gas because when the molecules hit the wall of the container, they are retarded by the unbalanced attractive force due to molecules behind. 1
Thus, the measured pressure p is less than the pressure due to an ideal gas under the same condition. A positive constant a is added to p. i.e. (p + k) is the pressure due to an ideal gas under the same condition. 0.5
Also, it causes the gas molecules to come together at low pressure in the course of condensation. Thus, it accounts for the other phases of real matter. 1
Intermolecular repulsive force
As molecules come very close to each other, they repel. Thus, the effective volume of a molecule is non-zero. This reduces the space in which other molecules could move. 1
The measured volume V is greater than the actual 'free volume'. Thus, a negative correction b should be made to V. i.e. (V - b) is the free-volume in which gas molecules can move. 1
 
Hosted by www.Geocities.ws

1