Chapter 1   Question 5
 
a. A stone is projected from a horizontal ground with a velocity u, making an angle q with the horizontal. 
(a)    Show that the path of the stone in air is parabolic. 
4 marks
 
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The initial horizontal and vertical components of the velocity of the stone are: 
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After time t, the horizontal and vertical displacements are 
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Eliminating t from equations (3) and (4), we have 
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Equation (5) is in the form of a parabola. Thus, the path of the stone is parabolic.
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b. Discuss how the vertical and horizontal components of the speed of the stone vary with time. Hence, find the range and the maximum height reached by the stone. 5 marks
 
Since the gravity acts vertically downward, the horizontal component of the speed of the stone is unchanged throughout the motion. 

The vertical component decreases as the stone moves up and increases as it moves down. Mathematically, 
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The range of the stone is the maximum horizontal displacement. This occurs when the stone hits the ground or when the vertical displacement is zero. 
The time of flight is given by putting y = 0 in equation (4): 
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The horizontal range is given by putting t = T in equation (3): 
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Maximum height is reached when the vertical component of the velocity is instantaneously zero. The time for max. height is given by putting vy in equation (7) to zero. 
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The maximum height is given by putting t = t' in equation (4): 
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c. Show that there is another angle of projection for the stone to hit the same target on the ground using the same speed of projection. Explain why the times of flight using these two angles of projection are different.  5 marks
 
The range of a projectile using projection angle q is 
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For the same range, let the other projection angle be f. Then, we have 
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From equation (8), the time of flight is 
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which is determined by the projection angle. Since  f = 90o - q, the time of flight for another projection angle is different.
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d. With a fairly accurate drawing, discuss how the direction with which the stone hits the ground depends on the angle of projection. (No mathematical proof is required.) 2 marks
 
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The path of the stone is parabolic. It is symmetrical about the dotted line PQ. Thus, the angle at which the stone hits the ground is the same as the angle of projection.  1
 
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