21 Oct 2001


ngle Between 2 Vectors

Let a and b be two non-zero vectors represented by OA and OB respectively. The angle between a and b is defined to be the angle between OA and OB, i.e. AOB.

Note that 0 AOB 180.


efinition of Scalar Product

The scalar product of two non-zero vectors a and b, denoted by a.b, is defined as

a.b = |a||b|cos q,� where q = angle between a and b.�


mportant Properties

  1. a.b = 0 a ^ b (if a 0, b 0)
  2. |a.b| = |a||b| a // b (if a 0, b 0)
  3. a.b = b.a
  4. a.(b + c) = a.b + a.c
  5. (la).b = l(a.b) = a.(lb) where l � R.
  6. a.a = |a|2
Note: a.b = a.c does not imply b = c.

For the 3 mutually perpendicular unit vectors i, j, k, we have

i.i = j.j = k.k = 1
i.j = i.k = j.k = 0


calar Product in Cartesian Form

Let a = a1i + a2j + a3k, b = b1i + b2j + b3k.� Then, using the properties of scalar product, we have

�a.b = (a1i + a2j + a3k).(b1i + b2j + b3k)�
= (a1i + a2j + a3k).(b1i) +�
(a1i + a2j + a3k).(b2j) +
(a1i + a2j + a3k).(b3k)
= a1b1 + a2b2 + a3b3
Hence
���
a1 b1
� � a2 . b2 �=� a1b1 + a2b2 + a3b3�
a3 b3


pplications of Scalar Product

1.��� To prove any two non-zero vectors are perpendicular

a.b = 0 a ^ b


2.��� To find the angle between two non-zero vectors.

��
a.b
cos q �=� ----
|a||b|


3.��� To find the projection of one vector on another.

Length of projection of a on b = |a.b^|


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