21 Oct 2001
ngle Between 2 Vectors
Let a and b be two non-zero vectors represented by OA and OB respectively. The angle between a and b is defined to be the angle between OA and OB, i.e. �
AOB.
Note that 0� �
� AOB �
180�.
efinition of Scalar Product
The scalar product of two non-zero vectors
a and b, denoted by a.b, is defined as
�
a.b = |a||b|cos q,� |
where q = angle between a and b.� |
mportant Properties
-
a.b = 0 � a ^
b (if a � 0, b
� 0)
-
|a.b| = |a||b| �
a // b (if a � 0,
b � 0)
-
a.b = b.a
-
a.(b + c) = a.b + a.c
-
(la).b = l(a.b)
= a.(lb) where l
� R.
-
a.a = |a|2
: a.b = a.c
does not imply b = c.
For the 3 mutually perpendicular unit vectors
i, j, k, we have
�
i.i = j.j = k.k = 1 |
i.j = i.k = j.k = 0 |
calar Product in Cartesian Form
Let a = a1i + a2j
+ a3k, b = b1i
+ b2j + b3k.� Then,
using the properties of scalar product, we have
�a.b |
= |
(a1i + a2j
+ a3k).(b1i +
b2j + b3k)� |
� |
= |
(a1i + a2j
+ a3k).(b1i) +� |
� |
� |
(a1i + a2j
+ a3k).(b2j) + |
� |
� |
(a1i + a2j
+ a3k).(b3k) |
� |
= |
a1b1 + a2b2
+ a3b3 |
Hence
�
����
� |
a1 |
� |
� |
b1 |
� |
� |
� |
�
� |
a2 |
�. |
� |
b2 |
� |
�=� |
a1b1 + a2b2
+ a3b3� |
� |
a3 |
� |
� |
b3 |
� |
� |
� |
� |
pplications of Scalar Product
1.��� To prove any two non-zero vectors are perpendicular
�
2.��� To find the angle between two non-zero vectors.
�
���
� |
� |
a.b |
cos q |
�=� |
---- |
� |
� |
|a||b| |
� |
3.��� To find the projection of one vector on another.
�
Length of projection of a on b
= |a.b^| |
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