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(If your problem is Algebra II Equations)

Don't Freak out! I'm gonna help you through this!

How to find "X" in a slope-intercept equation:

y=mx+b Find "x"

* y-b=mx Subtract "b" from both sides of the equation

*y-b/m=mx/m Divide by "m" on both sides of the equation and "m" becomes canceled out.

* y-b=mx "m" is canceled out

*y-b/m=x Answer

Now that was pretty easy wasn't it?

Lets try another one:

A=(b1+b2)h/2	Find "b1"
2A=(b1+b2)h	"A" is multiplied by 2
*2A/h=b1+b2	Both sides of the equation are divided by "h"
*2A/h-b2=b1	"b2" is subtracted from both sides
*2A/h-b2=b1	Answer

Are you gettin the hang of it?

Lets try just one more:

pV=nRT Find "R"

pV/n=RT Both sides are divided by "n" and "n" is canceled out on the right side.

pV/nT=R Both sides are divided by "T" and "T" is canceled out on the right side.

pV/nT=R Answer

I think you got it! Now lets put our skills to work!

Try solving a simple equation:

7x-3=2(x+6) Find "x"

7x-3=2x+12 2 is distributed to the right side of the equation

5x-3=12 2x is subtracted from both sides and 2x is canceled out on the right side.

5x=15 3 is added to both sides which makes 3 canceled out on the left side.

x=3 both sides are divided by 5 which makes 5 canceled out on the left side.

x=3 Answer

You're so good at this!

Try one more:

5x-7= -10x+8 Find "x"

15x-7=8 10x is added to both sides

15x=15 7 is added to both sides

x=1 Both sides are divided by 15

x=1 Answer

This is a toughie but I think you can do it! Just follow the directions and don't give up!

To find an equation containing the points (3,1) and (5,2):

First find your slope which is 1/2 Use equation (y2-y1) =m( x2-x1)

Equation in Point-Slope Form (y-1) = (.5) (x-3)

.5 is distributed throughout the equation y-1 = .5x - 1.5

1 is added to both sides of the equation y =.5x - .5

Equation in point-intercept form y = .5x - .5

Answer y = .5x - .5

YOU DID IT!!!

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y=mx+b	Find "x"
* y-b=mx	Subtract "b" from both sides of the equation
*y-b/m=mx/m	Divide by "m" on both sides of the equation and "m" becomes canceled out.
* y-b=mx	"m" is canceled out
*y-b/m=x	Answer

pV=nRT	Find "R"
pV/n=RT	Both sides are divided by "n" and "n" is canceled out on the right side.
pV/nT=R	Both sides are divided by "T" and "T" is canceled out on the right side.
pV/nT=R	Answer

7x-3=2(x+6)	Find "x"
7x-3=2x+12	2 is distributed to the right side of the equation
5x-3=12	2x is subtracted from both sides and 2x is canceled out on the right side.
5x=15	3 is added to both sides which makes 3 canceled out on the left side.
x=3	both sides are divided by 5 which makes 5 canceled out on the left side.
x=3	Answer

5x-7= -10x+8	Find "x"
15x-7=8	10x is added to both sides
15x=15	7 is added to both sides
x=1	Both sides are divided by 15
x=1	Answer

First find your slope which is 1/2	Use equation (y2-y1) =m( x2-x1)
Equation in Point-Slope Form	(y-1) = (.5) (x-3)
.5 is distributed throughout the equation	y-1 = .5x - 1.5
1 is added to both sides of the equation	y =.5x - .5
Equation in point-intercept form	y = .5x - .5
Answer	y = .5x - .5