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| Problem #1: 96 = -12c+36 -36 = -36 60 = -12c -12 -12 c = -5  |
For problem #1, you use simple Algebra I skills. To get the variable, c, by itself, you must first subtract 36 from both sides. This leaves you with 60=-12c. Since -12c is using multiplication, to get it by itself you must use division. Therefore you will divide both sides by -12. This will get your variable by itself and your problem is now complete. The answer is C = -5. |
| Problem #2: y= mx+b for x -b -b y-b = mx m m x = y-b
|
This is a unique problem
because it is all variables. However, you do it the same way you would
do a regular problem. Since you are trying to get your 'x' variable
alone, begin by subtracting 'b' from both sides. The new equation will
look like y-b=mx. Then you want to get your 'x' alone, so you would
divide both sides by m. Your 'x' is now on one side by itself so your
problem is complete. The answer is: X=y-b
m  |
problem #3: Give the equation for a line with slope= 3 through (2,9)....
y=3x+b |
To get the equation of the line, you first need to
determine which form you want to write the equation in. The form we are
using is slope-intercept. The format is y=mx+b whereas m= slope and b=
the y-intercept. They give you the slope so you can begin by inserting 3
where the m is. The new equation is y=3x+b. They give you two points so
you can solve for b by inserting those points into the equation. The new
equation reads 9=3(2) +b, which is also
9=6+b. To get the 'b' by itself, subtract 6 from both sides. This leaves you with b=3. Since you now know all of your variables, plug them into your equation. The final answer is y=3x+3. |
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