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Find an equation of the line through (3,5) with a slope of 1/2.

(3,5) slope of 1/2
the slope from (3,5) to (x,y) would be Y-5/X-3
Y-5/X-3=1/2
Multiply both sides by (x-3)
y-5=1/2(x-3)

Subtract 36 from each side of the equation. That will give you 60= -12c.
Divide each side by -12.
Your solution is c=5.

96=-12c+36
-36=
60=-12c
-12=-12
-5=c

SOLVE FOR R!!!!!!

I= PRT
PT PT
I/PT=R
Solve for R
Divide Both Sides By PT
Your Answer is I/PT = R

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	Find an equation of the line through (3,5) with a slope of 1/2.
(3,5) slope of 1/2 the slope from (3,5) to (x,y) would be Y-5/X-3 Y-5/X-3=1/2 Multiply both sides by (x-3) y-5=1/2(x-3)

	Subtract 36 from each side of the equation. That will give you 60= -12c. Divide each side by -12. Your solution is c=5.
96=-12c+36 -36= 60=-12c -12=-12 -5=c

	SOLVE FOR R!!!!!!
I= PRT PT PT I/PT=R	Solve for R Divide Both Sides By PT Your Answer is I/PT = R