| Equation For a Line: | For Slope Intercept Form |
| For
a line through (0,5) & parallel to y= -2.17x
+
3.82
y=-2.17x
+ b
|
To find the slope intercept form for the information given, you start by finding the slope. Since you know that when two lines are parallel they have the same slope, the slope for the line would be -2.17. If you understand this, you're well on your way. The next step is to plug the slope into your equation. To do this, you use the standard formula y=m(x)+b. With your slope plugged in, the equation now becomes y=-2.17x+b. Now the only thing left to do is to find the y intercept. To find this, you plug your coordinates into your equation in the place of y and x. The equation should now look like 5=-2.17(0)+b. Now that you have your equation set up properly, you can procede to solve the equation for b (your y intercept). Your first step in solving is to take care of the parenthesis. You would multiply the -2.17 by 0 giving you 0. You now have your variable by it's self and your answer, 5=b. Now all that's left to do is to plug your y intercept back into your equation. Your final equation should be y=--2.17x+5. |
Literal
Equation:  |
Formula for the area of a trapazoid |
| Atrap=
(1/2)(b1+b2)h
(Solving for b2)
A=(1/2)(b1+b2)h
2A -b1 = b2
|
The
first step in solving this equation is to deal with your parenthesis.
Since you're solving for b2, you want to get b2 by
it's self. The first way to start in doing this is to get rid of
the 1/2. In order to do get rid of the 1/2 you have to do the opposite
of what it's supposed to be doing in the equation (since it is supposed
to be multiplied, in order to get rid of it you have to divide by 1/2).
To make the problem less "messy" looking, you can also multiply by two
since it would be the same as dividing by 1/2. As always, you have
to do this to both sides of your equation. Your equation should now
look like 2A=(b1+b2)h.
The next step you need to take is to divide by the h since once again you
have to do the opposite (don't forget to divide to both sides of the equation).
your equation should now look like 2A=b1+b2.
h
Since you're trying to solve for b2, your need to get the b2 by it's self. To do this you subtract the b1 from both sides, giving your 2A-b1=b2. This h should be your final equation and solution. |
| Linear Equation: | |
|
t= 2-2[2t-3+3t)] t= 2-2(5t-3) t= 2-10t+6 t= -10t+8 +10t 11t=8
|
To start this equation you have to use the distributitive property. You have to first do your parenthesis. For this particular problem, you would first distribute the negative 3. After doing this your equation should now look like t= 2 - 2(2t-3+3t). You now continue to solve the equation by combining your like terms (add the 2t and 3t together to get 5t). The equation shold now be t= 2 - 2(5t-3). The next step would be to again distribute. You would multiply everything within the parenthesis by -2. Now your equation should read t= 2-10t+6. Once again, you combine your like terms (is it just me or is there a pattern here?) You combine your 2 and 6, giving you 8. The equation is now t=-10t+8. Since you want to solve for t, you need to get your variable on one side of the equation. To do this, you would have to do the opposite of it's function and add 10t to both sides. After doing this, the equation should look like 11t=8. Now you only have one thing left to do, and that is to divide the 11. When you do this, you get your solution of t=.73. |
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