Chris's Cool Algebra II Equations

Solving For X
1.5(4x-3)=2[x-(4x+3)]
1.5(4x-3)=2[x-4x-3]
1.5(4x-3)=2x-8x-6
1.5(4x-3)=-6x-6
6x-4.5=-6x-6
12x=-1.5
x=-.125
 1.  First you need to get rid of the parentehesis so you     distribute.
2.  Then you need to get rid of the brackets so you distribute.
3.  Then you combine like terms to get 1 value for x.
4.  Then yo need to get rid of the parenthesis.
5.  Subtract 6x from the right side so that now you have 12x on the left side.
6.  Now divide -1.5 by 12 to get the value of x.
Literal Equations
Q = V
M    Br

Q = (V) M
         Br

 1.  First, you know that you need to solve for Q, so you need to isolate this variable.

2.  In order to isolate the variable, simply multipy by M to recieve your answer.
Point-Slope Form
Write an equation in point-slope form given that the line passes through the point (0,5) 
and is parallel to the line 
y = -2.17x + 3.82

y - y1 = -2.17(x - x1)

y - 5 = -2.17(x - 0)

 1.  First of all you need to know the point slope form which is y - y1 = m(x - x1)
2.  Now you need to find the slope of the line and since you are parallel to the lne y = -2.17x + 3.82, then the slope of the line should be -2.17 because parallel lines have the same slope.
3.  Now all you have to do is fill in the points for y1 and x1.
4.  Now the equation should be y-5 = -2.17(x-0)

 

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