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      How to solve for g in the equation T=2p(1
                                                                         g
T=2p(1)½
          g
First you divide by 2
2pT=(1)½
       g
Next you will square both sides.
(2pT)2=(1)
             g
Following the previous step, you will multiply by g
g(2pT)2=1 As your final step you divide by (2pT)2
g=     1 
      (2pT)2
This is your answer

How to solve the equations  2Y-7 + 8Y-9 = 3Y-5
                                                  3          14         21
 
 
56Y-196 + 42Y-54 = 12Y-20 First you should find a common denominator (which is 84) and multiply everything by it.
104Y - 250 = 12Y - 20 Next you should combine all of your like terms.
92Y - 250 = -20 After that you should subtract 12Y by both sides.
92Y = 230 Following that you should add 250 to both sides.
Y = 2.5 Finally you should divide both sides by 92 leaving you with the answer.

How to write an equation in point slope, slope intercept, and standard form when the line goes through the point (4,6) and is perpendicular to the line
Y = -2x + 3
 
 
 
Y= mx + b I would first try to find slope intercept.
Y = 1 x + b
       2
You Find the slope by flipping and reversing the slope of the perpendicular line, which makes the slope -1 .
                 2
b = 4 You find b by plugging in the points (4,6).  B tells you your Y intercept.
Y = 1 x + 4
       2
This is your slope intercept form.
Y = 1 x + 4
       2 
To find your standard form you must get both variables on the same side.
-1 x  + y = 4
 2
Because you can not have a fraction on the side with the variables you must multiply everything by 2.
-x + 2y = 8 Because you can not have a leading negative on the side with the variables you must multiply everything by -1.
x - 2y = -8 This is your answer.
Y1 - Y2 = 1 (X1 -X2)
                 2
To find point slope I would take the slope from the slope intercept form and plug it in.
Y - 6 = 1 (X - 4)
            2
Next I would plug in the point given to me in the original problem giving me the point slope form.

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