Bo's Beautifully Bodatious Math
How to solve for g in the equation T=2p(1)½
g
| T=2p(1)½
g |
First you divide by 2 |
| 2pT=(1)½
g |
Next you will square both sides. |
| (2pT)2=(1)
g |
Following the previous step, you will multiply by g |
| g(2pT)2=1 | As your final step you divide by (2pT)2 |
| g= 1
(2pT)2 |
This is your answer |
How to solve the equations
2Y-7 + 8Y-9 = 3Y-5
3 14
21
| 56Y-196 + 42Y-54 = 12Y-20 | First you should find a common denominator (which is 84) and multiply everything by it. |
| 104Y - 250 = 12Y - 20 | Next you should combine all of your like terms. |
| 92Y - 250 = -20 | After that you should subtract 12Y by both sides. |
| 92Y = 230 | Following that you should add 250 to both sides. |
| Y = 2.5 | Finally you should divide both sides by 92 leaving you with the answer. |
How to write an equation in point
slope, slope intercept, and standard form when the line goes through the
point (4,6) and is perpendicular to the line
Y = -2x + 3
| Y= mx + b | I would first try to find slope intercept. |
| Y = 1 x + b
2 |
You Find the slope by flipping
and reversing the slope of the perpendicular line, which makes the slope
-1 .
2 |
| b = 4 | You find b by plugging in the points (4,6). B tells you your Y intercept. |
| Y = 1 x + 4
2 |
This is your slope intercept form. |
| Y = 1 x + 4
2 |
To find your standard form you must get both variables on the same side. |
| -1 x + y = 4
2 |
Because you can not have a fraction on the side with the variables you must multiply everything by 2. |
| -x + 2y = 8 | Because you can not have a leading negative on the side with the variables you must multiply everything by -1. |
| x - 2y = -8 | This is your answer. |
| Y1 - Y2 =
1
(X1 -X2)
2 |
To find point slope I would take the slope from the slope intercept form and plug it in. |
| Y - 6 = 1 (X - 4)
2 |
Next I would plug in the point given to me in the original problem giving me the point slope form. |