Abbey's Helpful Algebra Page


         x = 2x-6
         5
This is the original problem!
5(x=2x-6)                 x=10x-30
   5
First--multiply the entire equation by 5 to cancel out the 5 in x and you get x=10x-30
                            5
   x=10x-30                x+30=10x
+30      +30
add 30 to both sides to cancel out the -30 on the right side and you get x+30=10x
  x+30=10x                  30=9x
 -x          -x
subtract x from each side to remove the x from the left side and you get 30=9x
30=9x                       30=x
9     9                            9
divide each side by 9 to cancel out the 9x from the right side and you get 30=x
                                        9
30=x                          10=x
 9                                   3
reduce the fraction 30 to 10
                               9      3
and you get x=10
                       3
x=10
     3
You have just solved the equation!!

Now lets try another type of problem...
A LITERAL EQUATION

E=pA(T4-To4) Here is the original problem.  You will solve for A.
          E = pA(T4-To4)                    E  =pA
(T4-To4)       (T4-To4)             (T4-To4
First you should divide the everything by (T4-To4) and you get           E  =pA
            (T4-To4
         E  = pA                     E=p
(T4-To4)      p                p(T4-To4
     p
Next you divide both sides by p to get A by itself but since you have already have a denominator in the left side you can just add the p on to that.  You get              E=p
                p(T4-To4
            E=p
  p(T4-To4
This is your answer!!

How would you like to learn how to get an equation for a line???

Draw and equation for a line that crosses through (3,4) and has a slope of -2
                                      3
Here is our 3rd Problem!!
 y=mx+b                          y=-2 x +B
                                             3
You know that the equation for a line is y=mx+b where m=slope and b=y-intercept.
You know that the slope is -2 so you can put that in
                                          3
in place of the m in the equation.
y=-2 x +B                 4=-2 (3) +B
     3                               3
 
Next you can use the equation that you have so far and plug in the point that you know is on the line in place of the y and the x.  Then you should be able to find the y-intercept (B).
4=-2 (3) +B               4=-2+B
     3
To solve you should first multiply the -2 by 3
                                                         3
and you get -2.
   4=-2+B                    6=B
+2  +2
Add 2 to both sides to cancel out the -2 on the right side and you get 6=B
 6=B                          y=-2 x +6
                                       3
Plug in the 6 in place of the B (y-intercept) and you now have your equation!!!
 y=-2 x +6
      3
This is the equation you were looking for!!!!!!
 
    Go here to visit otherpages that explain how to solve equations.






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