Abstract

Obsolete... Starting from the equation of Schrodinger the wave function Ψ:

ΔΨ+ (8mπ² /h² )(E-e² /(4π² rε₀))Ψ = 0

The Schrodinger function for the first electron orbital in polar coordinate (1s) is:

Ψ_1s = 1/* (Z/r₀ )^{1. 5} e^-Zr/r₀

where r₀ is the radius of the first Bohr orbital 0.53 Angstrom.

If we consider the wave function Ψ = a(x,y,z)*e^{(2πi/h)*φ(x,y,z,t)} for the neutron and electron particles according to Louis de Broglie approximation the speed v of the particle is:

v = -(1/m)*grad φ(x,y,z,t) (The theory of double solutions of Louis de Broglie)

and the wave length is: λ=h/p=h/(m*v)=h/grad φ(x,y,z,t)

(2πi/h)*φ(x,y,z,t) = -Zr/r₀

so φ(x,y,z,t) = -h*Zr/(2r₀ * πi)

and the wave length is: λ=h/p=h/grad φ(x,y,z,t) = (2r₀ π)/Z

where Z is the number of protons (for mercury Z= 80).

According to the Quarks Informational Theory the neutron have the mass =1838* electron mass and the impulse is 1838 higher so we approximate that the wave length is 1838 higher

λ = 1838*(2r₀ π)/Z = 76.4Angstrom

According to the QIT the phenomenon will appear at both frequencies 233nm and 76.4 Angstrom because the photon is interacting with the mercury and we think that is in concordance with the experiment.