Solutions to Tutorial 3
By: Anuj Manuja
Q1. Unique Video Systems required a quarterly forecast for the upcoming year for its operations planning and budgeting. The following data are available about the past demand history:
|
Quarter |
1995 |
1996 |
1997 |
1998 |
|
1 |
10 |
10 |
10 |
|
|
2 |
30 |
50 |
50 |
|
|
3 |
50 |
50 |
60 |
|
|
4 |
10 |
10 |
20 |
|
a.
Using a linear trend exponential smoothing model, compute
the 1998 quarterly forecast. Assume a = b = 0.5, SQ3,1997 = 50, TQ3,1997 = 10.
Solution
St = a Dt
+ (1-a) (St-1 + Tt-1) (1)
Tt = b (St
– St-1) + (1-b) Tt-1 (2)
Ft+1 = St + Tt (3)
Þ SQ4 = a DQ4 + (1-a) (SQ3
+ TQ3) = 40
and TQ4 = b (SQ4
– SQ3) + (1-b) TQ3
= 0
Þ S0 = 40 and T0
= 0 (where subscript 0 represents Q4,1997, 1 represents Q1,1998 and so on)
Using (1), (2) and (3) we can now find
F0,1 = 40
F0,2 = 40
F0,3 = 40
F0,4 = 40
Where F0,1 represents forecast for period 1
(Q1,1998) made in period 0 (Q2,1998). It can be seen that forecasts for all
periods is same as T0 = 0.
b. Use a ratio seasonality and linear trend value model for forecasting demands. Estimate a good initial values using 1995 and 1996 data. Use hit and trial approach to come up with the smoothing constants (a, b, g) that best predict the 1997 demands.
Solution
For ratio seasonality and linear trend model the equations
are a follows
St+1 = a Dt+1/It-L+1
+ (1-a) (St + Tt) (1)
Tt+1 = b (St+1
– St) + (1-b) Tt (2)
It+1 = g Dt+1/St+1
+ (1-g) It-L+1
(3)
Ft = (St + Tt)It-L+1 (4)
For Initial values we use the method discussed in the class
i.e.
|
|
1995 |
1996 |
|
Q1 |
10 |
10 |
|
Q2 |
30 |
50 |
|
Q3 |
50 |
50 |
|
Q4 |
10 |
10 |
|
Total |
100 |
120 |
|
Avg. |
25 |
30 |
We assume the yearly averages to exist at the middle of the
year and quarterly demands given are in the middle of a quarter, and hence
Increase per year = 30-25 = 5
Increase per quarter = 5/4 = 1.25 = T0
|
Quarter |
Trend
Values (S) |
Seasonal
Indices (D/S) |
Avg. I |
Normalised i |
||
|
1995 |
1996 |
1995 |
1996 |
|||
|
Q1 |
23.125 |
28.125 |
.432 |
1.467 |
0.394 |
0.394 |
|
Q2 |
24.375 |
29.375 |
1.231 |
1.702 |
1.467 |
1.468 |
|
Q3 |
25.625 |
30.625 |
1.951 |
1.633 |
1.792 |
1.794 |
|
Q4 |
26.875 |
31.875 |
0.372 |
0.314 |
0.343 |
0.343 |
Þ S0 = 31.875, T0
= 1.25, I-3 = 0.394, I-2 = 1.468, I-1 = 1.794,
I0 = 0.343
F0,1 = (S0+T0)I-3
= 13.05
Now for determining the best possible values of a and b we use
the availble actual demand for 1997 and minimize the error of forecasts by
trying different combinations of a and b. This was done in excel (the file is available) and it was
found that the MAD (Mean absolute deviation is minimum for a = 0.1 and b = 1.
For a = 0.1 and
b = 1
This is the fore cast
for 1997 as done using data from 1995 and 1996
F0,1 = 13.05
F0,2 = 48.19
F0,3 = 60.19
F0,4 = 11.71
Corresponding to the above forecast MAD = 3.43
c.
Develop forecast for 1998
Solution
Using the above calculations and assuming g = 0.2 we get
S0 = 36.55, T0 = 3 , I-3 =
0.374, I-2 = 1.466, I-1 = 1.779, I0 = 0.381
F0,1 = (S0+T0)I-3
» 15
F0,2 = (S0+2T0)I-2
» 62
F0,3 = (S0+3T0)I-1
» 81
F0,4 = (S0+4T0)I0
» 19
d.
Develop a 3-quarterly moving average forecast for 1997.
Compare the error with that obtained by forecast model above
Solution
For 3-quarterly moving average Forecast = Avg. of previous 3
quarters
Using the data from part b. we get
|
Quarter |
Actual
Demand |
Forecast
from Moving Avg. |
Error
From Moving Avg. (abs) |
Forecast
from Part b (abs) |
Error
from Part b |
|
Q1 |
10 |
36.67 |
26.67 |
13.05 |
3.05 |
|
Q2 |
50 |
23.33 |
26.67 |
48.19 |
1.81 |
|
Q3 |
60 |
23.33 |
36.67 |
60.19 |
0.19 |
|
Q4 |
20 |
40.00 |
20.00 |
11.71 |
8.29 |
S |et| = 110 for
moving avg.
S |et| = 13.34
for ratio seasonality and linear trend
Hence the seasonality forecasting method is better.