So far we have studied that for Additive trend seasonality,

 

t = a(Dt/It-L) + (1-a)(St-1 + Tt-1)

Tt = b(St-St-1) + (1-b)(Tt-1)

It = g(Dt/St) + (1-g)It-L

Ft+m = (St + mTt)It-L+m

 

For a given data, it becomes a problem to determine initial points So,To. Here is an example to illustrate one method.

 

Example:

 

Following is sales data for 3 years for 4 quarters in each year.

 

 

1992

1993

1994

Q1

10

12

16

Q2

20

23

33

Q3

26

30

34

Q4

17

22

26

Average ->

18.25

21.75

 

 

Approach: The whole problem is divided into 2 major parts

§       One to determine initial points

§       Other to extrapolate for forecast

 

Initial point determination

Average of sales for past 2 years is placed at center of year and line joining them is formed. First data is taken as S0 and T0 is determined by equation of line

          which gives

          T0 = (21.75-18.25)/4 = 0.875 (per quarter)

 

Now, the estimation from the line is done. Values corresponding to each quarter that are lying on line are calculated. The results are

         

 

92

93

Q1

16.94

20.4

Q2

17.8

21.3

Q3

18.7

22.2

Q4

19.6

23.06

 

There is a seasonality attached with each data. So, seasonality indices are determined (actual demand/demand forecast by line), which are:

         

 

92

93

Average

Normalised

Symbol

1­

0.5904

0.5872

=0.5872/2+0.5904/2 =0.5888

0.59

I-3

Q2

1.123

1.079

1.0100

1.11

I-2

Q3

1.391

1.352

1.3720

1.38

I-1

Q4

0.869

0.9539

0.9115

0.92

I0

 

 

 

3.882

4.00

 

 

As we see, averages sum up to 3.882. To prevent things from going haywire, their summation is normalised to nearest integer=4. Normalisation is done by taking proportional values.

 

Also, I0,I-1...   have been denoted by considering end of 1993 as base.

 

Now, the forecasting part is as follows:

 

F0,1 = (S0+T0)I-3 = (23.06 + 0.875)*0.59 = 14.12

F0,2 = (S0+2T0)I-2 … and so on.

 

Now, D1=16     and taking a=0.2, b=0.1, g=0.1, we have

 

S1 = 0.2 (16/0.59) + (1-0.2)(S0 + T0) = 24.57

T1 = 0.9385   

I1 = 0.5961

 

Now, we have the forecasted data for Q1,1994. Actual sales data is also available.

By using these two, renormalisation is done as done previously.

This gives better indices to use.

 

How predictable is underlying data?

This is a question that poses a question mark on degree of complexity involved in method used. One simple method may be as good as one of the typical onesthat are computationally very expensive.

So, one has to know where to stop. In most cases, keeping things simple gives as good results as otherwise.

 

Reliability of method used depends on when forecast is being made and for when. For short intervals, these methods may yield good results but for long ranges, time-series methods may not be good to reply upon.

 

 



 

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