Posted by 5GJW on March 21, 1999 at 19:04:10 {MWZNJSg.uPfFk}:
In Reply to: ****Try this one, J.H.,5GJW,et.al. posted by ros on March 21, 1999 at 18:37:12:
Good try, but the correct answer is the speed of light, as in E = MC^2. You can't have more than 1C, or 3*10^8 m/s.
The source of that equation is a story problem that states:
Rocket 1 leaves Earth at .5C. Rocket 2 leaves earth at .6C, in the exact opposite direction. To an observer on rocket 1, how fast is rocket 2 going? The answer is .978C. How's that for different perceptions?
5GJW, coming back to Earth now