| Meadows Or Malls - Anwering the Unit Problem. 6 variables 12 constraints a)1.Gr+Gd=300 b)2.Ar+Ad=100 c)3.Mr+Md=150 d)4.Gd+Ad+Md=300 e)5.Ar+Mr=200 f)6.Ar+Gd=100 g)7.Gr=0 h)8.Ar=0 i)9.Mr=0 j)10Gd=0 k)11.Ad=0 l)12.Md=0 ABCFDE ABCFDG ABCFDH ABCFDI ABCFDJ ABCFDK ABCFDL ABCFEG ABCFEH ABCFEI ABCFEJ ABCFEK ABCFEL ABCFGH ABCFEI ABCFEJ ABCFEK ABCFEL ABCFGH ABCFGJ ABCFGK ABCFGL ABCFHI ABCFHL ABCFIJ ABCFIK ABCFJK ABCFJL ABCFKL There are 24 different equations that will be used in solving the problem thus creating 24 matrices, 24 coeffiecient matrices, 24 inverse matrices and 24 constant matrices. ABCFDE ( To make a coefficient list Gr Gd Ar Ad Mr Md at the top, mark 1 in every row for every variable you have in each equation) Gr Gd Ar Ad Mr Md [300] [1 1 0 0 0 0] [100] [0 0 1 1 0 0] [150] [0 0 0 0 1 1] [100] [0 1 1 0 0 0] [300] [0 1 0 1 0 1] [200] [0 0 1 0 1 0] ( Coefficient matrix of ABCFDE) Then multiply both matrices and get an answer matrix. [400] [250] [500] [250] [400] [450] I continued this process for each matrix multiplying it by a coeffiecient matrix and got all the answer matrixes which are: ABCFDE ABCFDG ABCFDH ABCFDI ABCFDJ ABCFDK ABCFDL ABCFEG ABCFEH [400] [400] [400] [400] [400] [400] [400] [400] [400] [250] [250] [250] [250] [250] [250] [250] [250] [250] [500] [300] [300] [300] [300] [300] [300] [200] [200] [250] [250] [250] [250] [250] [250] [250] [250] [250] [400] [200] [200] [200] [200] [200] [200] [350] [350] [450] [300] [150] [300] [100] [150] [ 0] [300] [100] ABCFEI ABCFEJ ABCFEK ABCFEL ABCFGH ABCFEI ABCFEJ ABCFEK ABCFEL [400] [400] [400] [400] [400] [400] [400] [400] [400] [250] [250] [250] [250] [250] [250] [250] [250] [250] [200] [200] [200] [200] [ 0] [200] [200] [200] [200] [250] [250] [250] [250] [250] [250] [250] [250] [250] [350] [350] [350] [350] [300] [350] [350] [350] [350] [200] [100] [100] [ 0] [150] [200] [100] [100] [ 0] ABCFGH ABCFGJ ABCFGK ABCFGL ABCFHI ABCFHL ABCFIJ ABCFIK ABCFJK [400] [400] [400] [400] [400] [400] [400] [400] [400] [250] [250] [250] [250] [250] [250] [250] [250] [250] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [250] [250] [250] [250] [250] [250] [250] [250] [250] [300] [300] [300] [300] [150] [150] [ 0] [ 0] [100] [100] [ 0] [100] [ 0] [ 0] [ 0] [100] [100] [100] ABCFJL ABCFKL [400] [400] [250] [250] [ 0] [ 0] [250] [250] [100] [100] [ 0] [ 0] After multiplying the 1st matrix with the coeffiecient matrix I found the inverse of the coeffiecient matrix and multiplied the inverse by the answer I got when I multiplied the 1st matrix with the coefficient matrix. There are the final answers in matrix form - Some of the equations didnt have inverses so they could not be finished ABCFDE ABCFDG ABCFDH ABCFDI ABCFDJ ABCFDK ABCFDL ABCFEG ABCFEH [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] [] ABCFEI ABCFEJ ABCFEK ABCFEL ABCFGH ABCFEI ABCFEJ ABCFEK ABCFEL [] [] [] [] [] [400] [400] [400] [400] [] [] [] [] [] [250] [250] [250] [250] [] [] [] [] [] [200] [200] [200] [200] [] [] [] [] [] [250] [250] [250] [250] [] [] [] [] [] [350] [350] [350] [350] [] [] [] [] [] [200] [100] [100] [ 0] ABCFGH ABCFGJ ABCFGK ABCFGL ABCFHI ABCFHL ABCFIJ ABCFIK ABCFJK [400] [400] [400] [400] [400] [400] [400] [400] [400] [250] [250] [250] [250] [250] [250] [250] [250] [250] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [ 0] [250] [250] [250] [250] [250] [250] [250] [250] [250] [300] [300] [300] [300] [150] [150] [ 0] [ 0] [100] [100] [ 0] [100] [ 0] [ 0] [ 0] [100] [100] [100] ABCFJL ABCFKL [400] [400] [250] [250] [ 0] [ 0] [250] [250] [100] [100] [ 0] [ 0] |