Solubility Equilibria

82) K_sp = 2.5 x 10^-10          [Ba²⁺] = 2.0 x 10^-8

      Ba(MnO₄)₂(s) Ba²⁺(aq) + 2MnO₄^-(aq)

      K_sp = [Ba²⁺] x [MnO₄^-]²

      2.5 x 10^-10 = 2.0 x 10^-8 x [MnO₄^-]²

      [MnO₄^-] = 0.11 M

      [KMnO₄] = 0.11 mol  MnO₄^-/L x 1 mol KMnO₄/1 mol  MnO₄^- = 0.11 M