Chemical Equilibrium

 

14) Keq = 0.0752          T = 480°C

      2Cl2(g) + 2H2O(g) 4HCl(g) + O2(g)

 

      (a) 4HCl(g) + O2(g) 2Cl2(g) + 2H2O(g)    

            Keq' = 1/Keq = 1/0.0752 = 13.3

 

      (b) Cl2(g) + H2O(g) 2HCl(g) + 1/2O2(g)

            Keq' = Keq1/2 = (0.0752)1/2 = 0.274

 

      (c) 2HCl(g) + 1/2O2(g) Cl2(g) + H2O(g)

           K'eq = Keq-1 = (0.274)-1 = 3.65

          

 

           


Hosted by www.Geocities.ws

1