Acceleration Due To Gravity of a Falling Golf Ball
<<I will put the picture of the falling golf ball in here once I get it from the school server.>>
Abstract:
A
golf ball was dropped from a standing height and tracked by a strobe light
flashing every 1/15th of a second. The experiment was recorded by a
digital camera whose the picture yielded a diagram showing the location of the
ball at different intervals in time. By using the time deduced from the flashes
of the strobe light and the distance the ball had fallen at that point, the
acceleration of the golf ball due to gravity was determined to be 10 m/s2
through graphing a distance versus time graph and subsequently, a velocity
versus time graph.
The purpose of this lab was to determine
the acceleration of an object due to gravity. This was done through tracking a
golf ball during a fall of approximately 100 cm.
The first step in this experiment was setting a strobe light to flash at
the rate of 900 flashes per minute, or one flash each 1/15th
of a second. A digital camera was set to take a picture of the golf ball
falling, with its shutter open for two seconds. Every time the strobe light
would flash, it would show the golf ball in a different location on its downward
path, and the digital camera was able to record each position in the duration of
the fall because its shutter remained open the whole time.
Thus, the strobe light was turned on and aimed at the golf ball, being
held by another person. The camera operator pushed the button on the camera to
set it going, and after four beeps and a fifth imagined beep, the ball was
dropped, and the strobe followed it on its descent. (The ball had to be caught
at the bottom so it didn’t bounce back into the picture.) The resulting
photograph was of a golf ball shown eight times alongside of a ruler taped on
the wall to use later for the measurements.
Now that we had a picture of the golf ball’s descent, we had to graph
its descent. This was done on a distance versus time graph. Along the x-axis of
the graph were the points for time, showing the 1/15ths
of a second. The y-axis represented the distance traveled, in meters. To
determine each of these points:
We
now had a graph of distance versus time of the falling golf ball. Distance
divided by time is velocity, so this graph was of the velocity of the falling
golf ball.
The next step was determining the acceleration of the golf ball, which in
this case was due to gravity, because it was simply let go of, not thrown, from
the zero point. To find the acceleration, we made a graph of velocity versus
time, since velocity divided by time equals acceleration.
Because of the said fact that velocity divided by time equals
acceleration, we determined that the slopes of the points on the velocity graph
would equal acceleration. (Slope equals rise over run, y over x, or, in our
case, distance over time.) By making little right triangles around each
mini-slope, we could find the height and base of each right triangle, and divide
them to get the slope of the hypotenuse of the triangle, which was the
acceleration.
These accelerations were plotted on a new graph against time, with time
remaining the value of the x-axis and the acceleration becoming the y-axis
values. Next, a line of best fit was graphed (NOT a line connecting all of the
points like in the distance versus time graph). The slope of the line of best
fit was the acceleration due to gravity for our data set.
To find the slope of the line of best fit, three points were chosen on
the line arbitrarily (these weren’t points from the original data set). Using
any point-slope formula, the slope was determined to be 10 m/s2.