Keywords: easytut

Next: The End Up: Non-Programmers Tutorial For Python Previous: File IO Contents
Subsections

- Exercises

# Dealing with the imperfect (or how to handle errors)

So you now have the perfect program, it runs flawlessly, except for one detail, it will crash on invalid user input. Have no fear, for Python has a special control structure for you. It's called `try` and it tries to do something. Here is an example of a program with a problem:

    print "Type Control C or -1 to exit"
    number = 1
    while number != -1:
        number = int(raw_input("Enter a number: "))
        print "You entered: ",number

Notice how when you enter `@#&` it outputs something like:

    Traceback (innermost last):
      File "try_less.py", line 4, in ?
        number = int(raw_input("Enter a number: "))
    ValueError: invalid literal for int(): @#&

As you can see the `int` function is unhappy with the number `@#&` (as well it should be). The last line shows what the problem is; Python found a `ValueError`. How can our program deal with this? What we do is first: put the place where the errors occurs in a `try` block, and second: tell Python how we want `ValueError`s handled. The following program does this:

    print "Type Control C or -1 to exit"
    number = 1
    while number != -1:
        try:
            number = int(raw_input("Enter a number: "))
            print "You entered: ",number
        except ValueError:
            print "That was not a number."

Now when we run the new program and give it `@#&` it tells us ``That was not a number.'' and continues with what it was doing before.

When your program keeps having some error that you know how to handle, put code in a `try` block, and put the way to handle the error in the `except` block.

# Exercises

Update at least the phone numbers program so it doesn't crash if a user doesn't enter any data at the menu.

Next: The End Up: Non-Programmers Tutorial For Python Previous: File IO Contents