%%HP: T(1)A(D)F(.);
 { {
"HALLAR EL AREA DEL TRIANGULO"
"CUYOS VERTICES SON A(1,-3),"
"B(3,3)Y C(6,-1).EMPLEANDO EL SENO"
"DEL ANGULO BAC."
"BC=(-1-3)^2+(6-3)^2=5"
"CA=(-3-(-1))^2+(1-6)^2=29"
"M1=3-(-1)/3-6=-4/3"
"M2=-3-(-1)/1-6=-2/-5=2/5"
"TAG=2/5-(-4/3)/1+(2/5)(-4/3)"
"TAG=26/7" } {
"=ARCTAG(26/7)=7455'"
"AREA=AB(SEN C)/2=5*29*SEN 7455'/2"
"    =13CM^2" "" ""
"" "" "" "" "" } }
HELP.3

