%%HP: T(1)A(D)F(.);
 { {
"DOS DE LOS VERTICES DE UN"
"TRIANGULO EQUILATERO SON LOS "
"PTOS (-1,1) Y (3,1) "
"HALLAR LA COORDENADA"
"DEL OTRO VERTICE"
"D=(3-(-1))^2+(1-1)^2"
"D=4"
"(Y-1)^2+(X-3)^2 ="
"(Y-1)^2+(X-(-1))^2"
"Y^2-2Y+1+X^2-6X+9="
} {
"Y^2-2Y+1+X^2+2X+1"
"-6X-2X+9-1=0"
"-8X=-8 ,X=1"
"4^2=(Y-1)^2+(1-3)^2"
"16=Y^2-2Y+1+4"
"Y^2-2Y-11=0"
"RESOLVER POR FORMULA"
"GENERAL."
"X=-B-+B^2-4AC/2A"
"X=1+23. (1,1+23)"
} } HELP.3

