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Date: Thu, 21 Jan 1999 01:05:11 +0530 From: [email protected] ( Sonal Ranjan) Add to Address Book Subject: WIPRO To: [email protected]

Wipro paper(System software)
July-1997
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PART --A
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1) abcD+abcd+aBCd+aBCD
   then the simplified function is
   ( Capital letters are copliments of corresponding letters
     A=compliment of a)

  [a] a   [b] ab  [c] abc  [d] a(bc)* [e] mone
  (bc)*=compliment of bc

  Ans:  e

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2) A 12 address lines maps to the memory of

 [a] 1k bytes  [b] 0.5k bytes [c] 2k bytes  [d] none

 Ans: b

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3) In a processor these are 120 instructions . Bits needed to impliment
   this instructions
   [a] 6  [b] 7  [c] 10  [d] none

  Ans: b

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4) In 8085 microprocessor READY signal does.which of the following
   is incorrect statements
   [a]It is input to the microprocessor
   [b] It sequences the instructions

  Ans : b
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5) Return address will be returned by function to
  [a] Pushes to the stack by call
  Ans : a
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6)
   n=7623
   {
        temp=n/10;
        result=temp*10+ result;
       n=n/10
   }

Ans : 3267
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7) If A>B then
      F=F(G);
   else B>C then
      F=G(G);
   in this , for 75% times A>B and 25% times B>C then,is 10000 instructions
   are there ,then the ratio of F to G
   [a] 7500:2500  [b]  7500:625  [c] 7500:625 if a=b=c else
                                     7500:2500
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8) In a compiler there is 36 bit for a word and to store a character 8bits are
needed. IN this to store
 a character two words are appended .Then for storing a K characters string,
 How many words are needed.
 [a] 2k/9  [b] (2k+8)/9  [c]  (k+8)/9 [d] 2*(k+8)/9 [e] none

 Ans: a
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9) C program code

   int zap(int n)
   {
    if(n<=1)then zap=1;
    else  zap=zap(n-3)+zap(n-1);
   }
   then the call zap(6) gives the values of zap
   [a] 8  [b]  9  [c] 6  [d]  12  [e] 15

  Ans: b
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PART-B
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1) Virtual memory size depends on
   [a] address lines    [b] data bus
   [c] disc space       [d] a & c    [e] none

 Ans :  a
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2) Critical section is
   [a]
   [b] statements which are accessing shared resourses
   Ans : b
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3) load a
   mul  a
   store t1
   load  b
   mul   b
   store t2
   mul t2
   add t1

  then the content in accumulator is

Ans : a**2+b**4
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4) question (3) in old paper
5) q(4) in old paper
6) question (7) in old paper
7) q(9) in old paper
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