RELATED RATE AND OPTIMIZATION PROBLEMS
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Emily
starts at point O at 8:00 am, and walks (5 km/h)to the East. Matthew starts at point B at 9:00 am, and walks (7 km/h) to the South. Question 1 (RELATED RATE PROBLEM): Question 2: (OPTIMIZATION PROBLEM) |
QUESTION 1 (RELATED RATE PROBLEM):
At what rate are Emily and Matthew separated at 11:00 am?
Let's say: t: The length of time that Emily has traveled
OA: The distance that Emily has traveled at t hours: x = 5t
BC: The distance that Matthew has traveled at t hours: 7 (t - 1) = 7t -7
r2 = OA2 + OC2
r2 = (5t)2 + [20- (7t - 7)]2
r2 = (5t)2 + (27- 7t)2
r2 = 25t2 + (729- 378t + 49t2)
r2 = 74t2 - 378t + 729
Differentiate both sides of the equation with respect to t
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r = (74t2 - 378t + 729)1/2
r = (74 x 32 - 378 x 3 + 729)1/2
r = 16.16 km
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Alternative solution to find the derivative
r = (74t2 - 378t + 729)1/2
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QUESTION 2 (OPTIMIZATION PROBLEM):
How many hours later Emily and Matthew will be closest?
r = (74t2 - 378t + 729)1/2
148t - 378 = 0
t = 2.55
for t = 2.55
r = (74t2 - 378t + 729)1/2
r = (74 x 2.552 - 378 x 2.55 + 729)1/2
r = 15.74 km (this is the closest distance they would have)