Sample #1
Cloth set
Ends per inch = 70
Picks per inch = 50
Fabric count
Count = length in yards x 453.6
wt in gram x 840
Warp count = 33.33
Weft count = 31.25
Warp & weft thread crimp
Crimp= (stretched length- unstretched length) x 100
unstretched length
Warp crimp = 2.56 %
Weft crimp = 11.42 %
Sample #2
Cloth set
Ends per inch = 29
Picks per inch = 53
Fabric count
Count = length in yards x 453.6
wt in gram x 840
Warp count = 9.375 = 10 Nc
Weft count = 43 Nc
Weft count grey = 9
Weft count blue = 11
Warp & weft thread crimp
Crimp= (stretched length- unstretched length) x 100
unstretched length
Warp crimp = 2.14 %
Weft crimp grey = 7.77 %
Weft crimp blue = 7.77%
Weft crimp fine = 8.88%
Q #1: weigh in grams per square meter and ounces per square yard of the given sample?
Sample 1:
A 10 x 10 sample is taken.
GSM = weight in gm of a 10 x 10 sample x 100
GSM = 0.987 x 100
GSM = 98.7.
To convert to ounces / sq: yd.
Ounces / sq: yd = 98.7 x 1met/1.0936 yd x I met/1.0936 yd x 1 ounce/28.35 gm.
Ounces / sq: yd = 2.911.
Sample 2:
GSM = Weight of fabric x 100 x 100 / 8 x 8
GSM = 0.935 x 100 x 100 / 8 x 8
GSM = 146.093
To convert to ounces per yard.
Ounces per yard = 146.093 gm/sq: yd x 1met/1.0936 yd x I met/1.0936 yd x 1 ounce/28.35 gm.
Ounce per sq: yard = 4. 308.
Q2. how many looms are required to produce 10,000 yards long fabric in one week if the speed of the loom is 210 PPM. Assume overall efficiency of 88 %.
Sample 1.
Since ppi of sample 1 is 50.
Production in inches/min,
= 210 picks/min x 1 inch/50 picks.
= 4.2 inch/min x eff (0.88).
= 3.696 inch/min.
Now calculating time in min in 1 week.
= 7 x 24 x 60 min
= 10080 min.
Now to find out production in inches in 7 days a week, we multiply.
= 3.696 x 10080
= 37255.68 inches.
To convert to yards,
= 37255.68/36 => production in yards = 1034.88 yds.
Since total requirement is 10,000 Yards, therefore.
= 10,000
1034.88
= 9.66 or 10 looms required.
Q2. how many looms are required to produce 10,000 yards long fabric in one week if the speed of the loom is 210 PPM. Assume overall efficiency of 88 %.
Sample 2.
Since ppi of sample 2 is 53.
Production in inches/min,
= 210 picks/min x 1 inch/53 picks.
= 4.2 inch/min x eff (0.88).
= 3.962 inch/min.
Now calculating time in min in 1 week.
= 7 x 24 x 60 min
= 10080 min.
Now to find out production in inches in 7 days a week, we multiply.
= 3.962 x 10080
= 39936.96 inches.
To convert to yards,
= 39936.96/36 => production in yards = 1109.36 yards.
Since total requirement is 10,000 Yards, therefore.
= 10,000
1109.36
= 9.01
Therefore 9 or 10 looms required.
