1. 6th July 1985.
Step 1: -
1: -85{year (last two digits)}
2: -6{date}
3: -5{according to table-2 the month code of July is 5}.
4: -1{according to table-1 the century code is 1}.
5: -21{Divide the leap year, which is just before the given year by 4 i.e. 84/4.The result is 21}.
Step 2: -
Add 85+6+5+1+21 and you will get 118.
Step 3: -
Divide 118 by 7 and the remainder you will get is 6.
According to the remainder you will find in table-3 that the weekday of the given day is Saturday.
2. 19th October 1996.
Step 1:-
1:-96{Year(last two digits)}
2:-19{Date}
3:-6{According to table-2 the month code of October is 6}
4:-1{According to table-1 the century code is 1}
5: -23{Divide the leap year, which is just before the given year i.e. 92/4.The result is 23}
Step 2:-
Add 96+19+6+1+23.You will get 145.
You must also add 1 as the given year is a leap year and the month is after February. You will get 146.
Step 3:-
Divide 146 by 7 and you will get 6 as the remainder.
By table-3 you will know that the weekday of the given day is Saturday.
3. 1st January 1900.
Step1: -
1:-00{year (last two digits)}
2: -1{date}
3: -6{according to table-2 the month code of January is 6}.
4: -1{according to table-1 the century code is 1}
5:-0{there is no need to calculate the leap year here because it is a century year}.
Step2: - ;
Add 1+6+1 to get 8.There is no need to add 1 since 1900 is not a leap year since it is a century year, which is not divisible by 400.
Step3: -
Divide 8 by 7 and you will get 1 as the remainder.
According to table-3 you will find that the weekday of the given day is Monday.
4. 15th August 2000
Step1: -
1:-00{year (last two digits)}
2: -15{date}
3: -1{according to table-2 the month code of august is 1}
4: -6{according to table-1 the century code is 6.
5:-0{there is no need to calculate the leap year here because it is a century year}.
Step2: -
Add 15+1+6 and the result is 22.
You should also add 1 as the year is a leap year since it is a century year which is divisible by 400 and the month is after February.
So you will get 22+1 which is 23.
Step3: -
Divide 23 by 7 and you will get 2, as the remainder.
The weekday of the given day, is Tuesday from table -3.
5. 5th September 2008.
Step1: -
1:-08{Year (last two digits)}
2: -5{Date}
3: -4{according to table-2 the month code of September is 4}.
4:-0{According to table-1 the century code is 0 because the year is not a century year even though the remainder is 0}.
5: -1{Divide the leap year that is just before the given year by 4 i.e. 4/1 .The result is 1}
Step2: -
Add 8+5+4+1.The result is 18. Also add 1 as the year is a leap year and the month is after February. The result is 19.
Step3:-
Divide 29 by 7 and the remainder is 5 .
See table-1 and you will find that the weekday of the date is a Friday.