The Substitution Method
I don't know what a chef has to do with the substitution method, but oh well... dAnd now, the moment you've all been waiting for:
IT'S TIME TO LEARN ABOUT THE SUBSTITUTION METHOD!!!!!
The Steps:
| Step 1: fSolve one of the equations for one of its variables. |
| Step 2: gSubstitute the expression from Step 1 into the other equation and solve for the other variable. |
| Step 3: fSubstitute the value from Step 2 into the revised equation from Step 1 and solve. |
Now, using those steps, let's try to solve a linear system using substitution!
3x + 4y = -4 fffffffffEquation 1
dddddddddddddddddddddddddddddddddddddddddddddddd x + 2y = 2 ssssssssEquation 2
dddddddddddddddddddddddddddddddd
SOLUTION: 1. sSolve equation 2 for x. sdfddddddssss s x + 2y = 2dddddddddWrite Equation 2. ssffffffffff dddfffx = -2y + 2ffffffffff fff Revised Equation 2 2. hSubstitute the expression for x into Equation 1 and solve for y. ffffffffffff fffffff3x + 4y = -4ssssssssssWrite Equation 1. ff ssss 3(-2y + 2) + 4y = -4 sa fffffffff Substitute -2y + 2 for x. hhhhhhhhhhhhhhhhh y = 5ddddddddd Solve for y. 3. fSubstitute the value of y into revised Equation 2 and solve for x. fffffffffffdddddd x = -2y + 2ggggggggg Write revised Equation 2. fffffffffffffffffffx = -2(5) + 2ddddddddd Substitute 5 for y.g ggsssssssssssdgggg xf=f-2f ff ssssssssSimplify.f
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Now that wasn't so bad, was it??