Broadway Presents:
MARVELOUS MATH

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Now, don't get too excited I'm a normal person just like you....can you believe it??? As you make your long, dramatic journey you will find that Mrs. Felz Algebra 2 class has been diving into substitution problems. I know what you must be thinking...well, you're scared, right? Well....this page is designed to erase all of your difficult memories dealing with this wretched word: substitution. (you can thank me later)!

The Very First Substitution Problem is:
2x + y = 6 
3x + 4y = 4 


 

STEP 1:
y = 6 – 2x

STEP 2:
x + 4y = 4

3x + 4(6 – 2x) = 4
 
STEP 3: 
3x + 24 – 8x = 4
-5x = -20
x = 4
STEP 4:
2x + y = 6
2 * 4 + y = 6

y = -2   

The answer is: (4,-2)

 

STEP 1:
We have to solve the first equation for Y because its y-term has a coefficient of 1.

STEP 2:
Y and 6 – 2x are equivalent. We can substitue 6 – 2x for y in the second equation. 
STEP 3:
This gives us an equation in one variable, doesn’t it?? Well, now we can solve for x.
STEP 4:
Good. Now we can substitute 4 for x in either equation and solve for y.


 

 
 
Ok. Now that you have apparently made it through the substitution problems....I graduate you to the level of linear combinations! (That's what you get for being smart!)
   linear combination problem: 
3x - 4y = -1
-3x + 2y = 0
Step 1: We know that 3x - 4y and -1 are equivalent expressions. Thereforee, we can use the addition property to add the same quantity to both sides of the second equation. We then can add 3x - 4y to the left side and -1 to the right side of the second equation.
Step 2: Now we can solve this equation easily, finding y=1/2. Then, we substitute 1/2 for y in either of the original equations.
Step 1: -3x + 2y + (3x - 4y) = 0 ++ 1(-1)
 
 
 

Step 2: -3x + 2y = 0
           -3x + 2(1/22) = 0
                -3x + 1 = 0
                  x=1/3
The answer is:  (1/3, 1/2)


 

Because you have been working so very hard to prowl your way through these extremely hard problems I am going to give you a break with a word problem!!! Please look to your left at this time!                                               
A bear arrives at the Roberts' store with 8 small boxes and 5 large boxes. The total charge for the boxes, without tax or delivery charges, is $184. A large box costs $3 more than a small box. What is the cost of each size box?
Step 1: 8x + 5y = 184
              y= 3 + x
Step 2: If you would like to check your answer then... 8 times $13($104) plus 5 times $16($80) is $184. $16 is $3 more than $13. Therefore, both conditions are satisfied!
    A large box costs $16, a small box costs $13.
 
Step 1: There are two statements in the problem. Each can be translated into an equation. 
x= the cost of a small box.
y= represents the cost of a large box.
Step 2: When we substitute 3 = x for y in the first equation, we get 8x + 5(3 +x) = 184. When we solve for x we realize that x=13. Since y= 3 + x, y=16.

 
 
 

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