FROM MY BRAIN TO YOURS: ALGEBRA II
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THE FOLLOWING INFORMATION MIGHT BE OF USE TO YOU!!!7x + 2y = -1 3x - 4y = 19
2y = -7x - 1 4y = -3x - 19
y = -3.5x - 0.5 y = -0.75x - 4.75WHEN SOLVING GRAPHICALLY:
1. Put them into regular y = mx + b form
- Move over the y.
- Divide appropriate numbers
2. Graph the first one.
3. Graph the second one.
4. Use the intersecting tool, and find out the coordinates of the intersection.
OR
You could use a table to substitute for the x and the y, and see which ones work.
2x + y = -6 y = -2x - 6 (2)(-4)+ y =-6
3x + y = -10 3x + (-2x - 6) = -10 -8 + y =-6
x - 6 = -10 +8 +8
+ 6 +6 y = 2
x = -4WHEN SOLVING WITH SUBSTITUTION:
1. Put the top line into the y = mx + b form.
2. Once you find what y equals, substitute in the bottom line for y.
3. Work it down and find x.
4. Then substitute x in either line ( it dosen't matter which ) and find y. Together, they are the answer.
The perimeter of a rectangular field is 628m. The length of the field exceeds its width by 6m. Find the dimensions. 2l +2w = 628m 628 L = 320/2 = 160
2 -320 p; W = 308/2 = 154
314 + 6 = 320 308The length equals 160m.
The width equals 154m.WHEN SOLVING WITH LINEAR EQUATIONS:
1. Use the formula to start. ( 2l + 2w = 628 )
2. Divide 628 by 2, and add 6 to find your TOTAL LENTH.(Divide the 320 by 2 to get 1 dimension. )
3. Subtract the 320 from 628 ( 308 ) to find the TOTAL WIDTH. ( Divide the 308/2 to get the other dimension.)
4. L = 160m
W = 154mSOME OF MY FAVORITE LINKS: CANDYSTAND.COM MRS. FELZ'S PAGE MY FELLOW CLASSMATE'S PAGES JASON S. DRIVE SAFELY !!!!!!!