SWOPE'S SLOPES
Linear EquAtiOnsLinear Equations are equations that when solved, 1 variable equals 1 number.
| 5y
- 6 = 2 - 4y
7 7 |
Given problem. |
1 |
You
want to get rid of the fractions, so you
multiply both sides by 7 to 1 cancel out the 7 in the denominator. |
| 5y - 6 = 14 - 28y | Your
new problem after multiplying by 7
1 |
|
5y +28y |
Now
you can start to actually work the
problem. You need all alike variables on one side. step one: add 28y to both sides step two: add 6 to both sides |
| 33y = 20 | Your new problem after combining like terms. |
| Now
you need to isolate the 'y'.
All you have
to do is divide by 33 . |
|
| y
= 20
33 |
Your
answer, y = 20
33 |
LITERAL EQUATIONS
Literal Equations have more than 1 variable. They are solved for a specific variable.
A numerical answer is not available for this type of equation.
| So = Do
: Di
Si Di |
Given problem. The ':' means to find for, so you are solving for Di. |
| Di
( So ) = ( Do ) 1 Si |
First, multiply both sides
by Di.
1 This gets Di on the left, and cancels it on the right. |
| Di (So) = Do
Si |
Your new problem. |
| Di |
Now you have to get Di by itself.
To do this, multiply both sides by Si.
So |
| Di = DoSi
So |
Your answer, Di = DoSi
So |
WRITING LINEAR EQUATIONS
---Slope Intercept Form---
Slope Intercept Form is y=mx+b, where m is the slope and b is the y-axis intercept.
| A
line goes through point (5,2) and its slope is -3
5 |
Given problem. Put into y=mx+b form. |
| 2
= -3 (
5) + b
5 |
Put
the points into the 'x'(5)
and 'y'( 2) spots.
Put the -3
in as the 'm'
5 |
| 2
= -3 ( |
The 5 in the denominator cancels the 5 in the numerator. Leaving you with -3. |
|
2 = +3 |
Your new problem. Now you are trying to isolate 'b'. Add 3 to both sides , and that will give you what b equals. |
| 5 = b | B equals 5. |
| y
= -3x
+ 5
5 |
Go back to y=mx+b and plug in your 'b' and 'm' values. |
| y
= -3 x + 5
5 |
Your
answer, y = -3 x + 5
5 |
, THERE'S ANOTHER
WAY!
~ ~ ~Point Slope Form~ ~ ~
Point Slope Form is Y - Y1 = M (X - X 1), where X1 and Y1 are the coordinates of a point on the line and M is the slope.
| A
line goes through point (0,-1) and has a slope of 3.
2 |
Given problem. You are wanting to put this info into Y- Y1 = M (X-X1) form. |
| Y
+ 1 = 3
(X - 0)
2 |
Substitute in your 'x' and ' y' values (given as the coordinates from the point) and also your 'm' value, or slope. Remember that the negatives turn into a positive (with the 1). |
| Y
+ 1 = 3 (X - 0)
2 |
Your new problem. Oddly enough, this is also your answer. |
| Point Slope Form is very quick and easy. It also can go into y=mx+b with a few more steps. |
|
| Y
+ 1 = 3x
2 |
First
distribute the 3 to the X and 0.
2 |
| Y
|
Now just subtract the 1 from both sides . |
| Y
= 3 x - 1
2 |
This
leaves you with your y=mx+b answer, which is, y = 3 x-1
2 |
* * * Standard Form* * *
Standard Form is Ax + By = C, where
A is the 'x' value of a point, B is the 'y' value
and C is the y intercept. All the
variables are on one side.
| A line goes through
point (2,3) and has a slope of -1
2 |
Given problem. Standard Form is mainly used when the equation is already in Point Slope or Slope Intercept form. |
| 3 = -1(2)
+ b
2 |
First put it into y=mx+b form, and solve for 'b'. |
| 3 = -1( |
The 2's cancel, leaving you with a new problem. |
| 3 =
+1 4 = b |
Your new problem. Now, you add one to both sides and that will solve for b. B equals 4. |
|
y =
+ 1x 2 |
Go back to y=mx+b and plug in all your values. Now we start putting it into Standard Form. Add 1x to both sides. 2 |
| ( |
Your new problem. Now the variables are on one side. BUT in Standard Form there are NO FRACTIONS. All you have to do is multiply both sides by 2 . |
| x + 2y = 8 | Your answer, x + 2y = 8 |
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Hint: If the problem
is given in Standard Form and is wanting you to put it into Slope Intercept
or Point Slope Form, there is a quick and easy formula to help you find
the slope and y intercept. Slope = A and Y inter. = C
-B
B |
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