Jeremy's
Math Help Site
Linear Equations
Jeremy's
Math Help Site
| Equation | Explanation |
| q=(3/2)q-4 | the starting equation (the problem) |
| 2q=3q-8 | multiply everything by 2 to get rid of the denominator |
| -q=-8 | subtract 3q from both sides to get all variables to one side |
| q=8 | divide both sides by -1 (the coefficient of q) |
Literal Equations
| Equation | Explanation |
| a=(vf-vi )/t | we'll use the formula for acceleration (solve for vi) |
| at=vf-vi | multiply by t to get rid of the denominator |
| at-vf=-vi | subtract vf from each side |
| -at+vf=vi | divide both sides by -1 (the coefficient of vi) |
| vi=vf-at | rearrange to make better appearance |
3 forms of a line Equations
| Equations | Explanations |
| line with slope 2 and passes through (0,4) | the problem |
| y-4=2(x-0) | begin with Point-Slope form (its easiest) |
| y-4=2x | use distributive property |
| y=2x+4 | add 4 to both sides (this is Slope-Intercept form) |
| -2x+y=4 | subtract 2x from both sides |
| 2x-y=-4 | multiply everything by -1 to make better appearance (this is Standard form) |
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